如何解决我已经开始在Pygame中编写《飞扬的小鸟》游戏，但我卡住了如何显示《小鸟与竹子之间的碰撞》？
所以我对Pygame还是很陌生，我一直在研究如何在柔和的鸟类游戏中显示鸟类与竹子之间的碰撞，以及如何在未与竹子发生碰撞的情况下继续运行它。 我还没有编写完整的代码，所以请告诉我该如何显示碰撞（带有步骤，为什么要使用它？在pygame中使用）以及碰撞后屏幕上显示GAME OVER的源代码。（可选） ） （提前感谢：）
import pygame
pygame.init()
WINDOWWIDTH = 820
WINDOWHEIGHT = 480
win = pygame.display.set_mode((WINDOWWIDTH,WINDOWHEIGHT))
pygame.display.set_caption("The Flappy Bird Game")
birdload = [pygame.image.load('C:/Users/Vinod/Desktop/Flappy Bird/flapbird.png')]
bgimg = pygame.image.load('C:/Users/Vinod/Desktop/Flappy Bird/bg.jpg')
clock=pygame.time.Clock()
UP = 'up'
DOWN ='down'
LEFT ='left'
RIGHT = 'right'
WHITE =(255,255,255)
BLACK = (0,0)
RED = (255,0)
GREEN = (0,0)
DARKGREEN = (0,155,0)
DARKGRAY = (40,40,40)
YELLOW = (255,0)
ORANGE = (255,165,0)
BGCOLOR = BLACK
broWN = (90,39,41)
score = 0
def showstartscreen():
global BASICFONT,FPS
FPS = 15
BASICFONT = pygame.font.Font('freesansbold.ttf',18)
titleFont = pygame.font.Font('freesansbold.ttf',100)
titleSurf1 = titleFont.render('The Flappy Bird!',True,WHITE,YELLOW)
titleSurf2 = titleFont.render('The Flappy Bird!',ORANGE)
degrees1 = 0
degrees2 = 0
while True:
win.fill(BGCOLOR)
rotatedSurf1= pygame.transform.rotate(titleSurf1,degrees1)
rotatedRect1 = rotatedSurf1.get_rect()
rotatedRect1.center= (WINDOWWIDTH / 2,WINDOWHEIGHT / 2)
win.blit(rotatedSurf1,rotatedRect1)
rotatedSurf2 = pygame.transform.rotate(titleSurf2,degrees2)
rotatedRect2 = rotatedSurf2.get_rect()
rotatedRect2.center = (WINDOWWIDTH / 2,WINDOWHEIGHT / 2)
win.blit(rotatedSurf2,rotatedRect2)
drawPressKeyMsg()
pygame.display.update()
clock.tick(FPS)
degrees1 += 3 #rotate 3 degrees each frame
degrees2 += 7 #rotate by 7 degrees per frame
def drawPressKeyMsg():
pressKeySurf = BASICFONT.render('Press a key to play.',DARKGRAY)
pressKeyRect = pressKeySurf.get_rect()
pressKeyRect.topleft = (WINDOWWIDTH - 200,WINDOWHEIGHT - 30)
win.blit(pressKeySurf,pressKeyRect)
def terminate():
pygame.quit()
class bird(object):
def __init__(self,x,y,width,height,end):
self.x = x
self.y = y
self.width = width
self.height = height
self.end = end
self.path = [self.x,self.end]
self.flyCount = 0
self.vel = 3
self.hitBox = (self.x + 17,self.y + 2,31,57)
self.visible = True
def draw(self,win):
if self.flyCount + 1 >= 27:
self.flyCount = 0
if not(self.standing):
win.blit(birdload[self.flyCount//3],(self.x,self.y))
self.flyCount +=1
else:
win.blit(birdload[0],self.y))
self.hitBox = (self.x + 17,self.y + 11,29,52)
#pygame.draw.rect(win,(255,0),self.hitBox,2)
def hit(self):
self.isJump = False
self.jumpCount = 10
self.x = 100
self.y = 410
self.flyCount = 0
font1 = pygame.font.SysFont('comicsans',100)
text = font1.render('-5',1,0))
win.blit(text,(250 - (text.get_width()/2),200))
pygame.display.update()
i = 0
while i < 200:
pygame.time.delay(10)
i += 1
for event in pygame.event.get():
if event.type == pygame.QUIT:
i = 201
pygame.quit()
def fly(self):
if self.vel > 0:
if self.x + self.vel < self.path[1]:
self.x += self.vel
else:
self.vel = self.vel * -1
self.flyCount = 0
else:
if self.x - self.vel > self.path[0]:
self.x += self.vel
else:
self.vel = self.vel * -1
self.flyCount = 0
def bamboo():
bamb0 = pygame.draw.rect(win,broWN,(310,28,140))#left,top,height
pygame.display.flip()
bamb1 = pygame.draw.rect(win,230,250))
pygame.display.flip()
bamb2 = pygame.draw.rect(win,(410,100))#left,height
pygame.display.flip()
bamb3 = pygame.draw.rect(win,160,320))#left,height
pygame.display.flip()
bamb4 = pygame.draw.rect(win,(510,110))#left,height
pygame.display.flip()
bamb5 = pygame.draw.rect(win,180,300))#left,height
pygame.display.flip()
bamb6 = pygame.draw.rect(win,(600,240))#left,height
pygame.display.flip()
bamb7 = pygame.draw.rect(win,320,160))#left,height
pygame.display.flip()
bamb8 = pygame.draw.rect(win,(700,120))#left,height
pygame.display.flip()
bamb9 = pygame.draw.rect(win,200,280))#left,height
pygame.display.flip()
bamb10 = pygame.draw.rect(win,(770,190))#left,height
pygame.display.flip()
bamb11 = pygame.draw.rect(win,250,230))#left,height
pygame.display.flip()
class sticks(object):
bamboo()
def collision():
if bird.x == sticks.x and bird.y == sticks.y:
print("Game Over")
gameover()
while True:
if checkForKeyPress():
pygame.event.get() # clear event queue
return
else:
True()
请最后参考“类杆”中的“ def碰撞”，我知道我添加的代码可能是错误的...请仅为此部分回答... 问候， 西田塔库尔。
解决方法
设计对象时，通常是针对单个对象，所以说“树”而不是“森林”，因为森林是一组树。 sticks类已经朝着正确的方向发展，但是随后使用名为bamboo()的函数来知道它们的位置并绘制所有它们。
使您的代码更易于使用的方法是将这两个代码结合在一起，从而使单个对象负责每根竹子的位置，绘制和碰撞。多个对象被分组在一起，以便在Python“容器”数据结构（如列表）中轻松访问。
首先让我们新建一个Bamboo：
class Bamboo:
def __init__( self,x,y,width,height ):
self.image = pygame.Surface( ( width,height ) )
self.rect = self.image.get_rect()
self.rect.x = x
self.rect.y = y
# currently the image is a brown rectangle
self.image.fill( BROWN )
def draw( self,surface ):
surface.blit( self.image,self.rect )
def move( self,dx,dy ):
self.rect.move_ip( dx,dy )
def collidesWith( self,other_rect ):
result = self.rect.colliderect( other_rect )
return result
关于Bamboo实体的所有内容都包含在Bamboo对象中。由于此对象了解有关自身的所有知识（而无其他知识），因此很容易实现collidesWith()函数，图形等。
但是我们如何创建所有这些竹签-循环填充列表。
### Create the list of Bamboo
all_bamboo = [] # list to hold the final objects
# List of initial locations and sizes
initial_locs = [ (310,28,140),(310,230,250),(410,100),160,320),(510,110),180,300),(600,240),320,160),(700,120),200,280),(770,190),250,230) ]
# loop through the locations,making Bamboo,appending to list
for location in initial_locs:
x,height = location # unpack location
new_bamboo = Bamboo( x,height ) # create a Bamboo
all_bamboo.append( new_bamboo ) # move to list
因此，现在您已经创建了所有Bamboo对象，并将其移至名为all_bamboo的列表中。列表中的所有内容使绘制，移动和检查碰撞变得轻而易举。
您不会在问题中显示主循环函数，所以我自己做：
### Main Loop
clock = pygame.time.Clock()
done = False
while not done:
# Handle user-input
for event in pygame.event.get():
if ( event.type == pygame.QUIT ):
done = True
elif ( event.type == pygame.MOUSEBUTTONUP ):
pass # TODO - handle mouse-clicks
elif ( event.type == pygame.KEYUP ):
pass # TODO - handle player-input
### Update the window
window.fill( WHITE ) # fill the background
# draw the sprites
player_bird.draw( window ) # draw player
for bamboo in all_bamboo: # draw all bamboo
bamboo.draw( screen )
pygame.display.flip() # send the updates to the screen
### Check for collisions & move bamboo
bird_rect = pygame.Rect( bird.hitbox ) # location of bird
for bamboo in all_bamboo: # for each stick of bamboo
if ( bamboo.collidesWith( bird_rect ) ): # does it collide?
# Bird hit bamboo,now what?
bird.hit() # ouch!
# move the bamboo 1 pixel left
# so it looks like the bird moves forward
bamboo.move( -1,0 )
clock.tick(60)
pygame.quit()
每当您发现自己需要一组项目时，（可能是乌云密布）就会想到代表单个实体的单个对象，然后是容器数据结构来容纳它们。
因此，当您发现自己向对象的核心部分中不添加代码时，例如说：在collidesWith()函数中添加“ game over”子句，您可以问自己“正在绘制图形”游戏结束画面真的是竹棍的责任吗？！”这些想法可以保持一个好的设计。这有助于防止在不相关的位置放置逻辑位置不佳的意大利面条代码。
注意：上面未测试，已调试代码。错误和遗漏应该是可以预期的。
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