如何解决复制工作簿并粘贴到另一个工作簿下面的MS Excel
首先,我打开一个SubWorkbook,然后从工作表中复制数据以更新MainWorkbook(在下面粘贴):
当我尝试从刚打开的工作簿中为工作表设置变量时,会出现问题。它说:“下标超出范围”。
它发生了什么以及如何修复,或者我必须从另一种方式走错方向。
Sub Data_Inbound()
Dim mywb As Workbook
Dim FName As String
Dim wscopy As Worksheet
Dim wsDest As Worksheet
Dim lcopyLastRow As Long
Dim lDestLastRow As Long
Set mywb = ActiveWorkbook
On Error GoTo errHandler:
FName = Application.GetopenFilename(filefilter:="Excel Files,*.xlsx*",Title:="Please select an Excel file")
Workbooks.Open FileName:=FName
Set wscopy = Workbooks(FName).Worksheets(Sheet1)
Set wsDest = Workbooks(mywb).Worksheets(Sheet1)
lcopyLastRow = wscopy.Cells(wscopy.Rows.Count,"A").End(xlUp).Row
lDestLastRow = wsDest.Cells(wsDest.Rows.Count,"A").End(xlUp).Offset(1).Row
wscopy.Range("A2" & lcopyLastRow).copy _
wsDest.Range("A" & lDestLastRow)
wsDest.Activate
errHandler:
MsgBox "Error " & Err.Number & " (" & Err.Description & ") in procedure Data_Inbound"
Exit Sub
End Sub
我看到其他人,他们有相同的问题,但是他们使用工作表名称,对我来说,我使用了一个变量变量,但这会导致错误: 其他人:
Set wscopy = Workbooks("Warranty Template.xlsm").Worksheets("Pivottable")
解决方法
从封闭的工作簿复制/粘贴
- 如果看到此消息,则代码已成功运行。如果没有,则出现问题,并且“立即”窗口 CTRL + G 中会出现一条消息。
代码
Option Explicit
Sub Data_Inbound()
' Initialize error handling.
Const ProcName As String = "Data_Inbound"
' Do not use error handling while developing the code.
On Error GoTo clearError ' Turn on error trapping.
' Define Destination Workbook.
Dim wb As Workbook
Set wb = ThisWorkbook ' The workbook containing this code.
' Define Source Workbook Name.
Dim srcName As String
srcName = Application.GetOpenFilename(filefilter:="Excel Files,*.xlsx*",_
Title:="Please select an Excel file")
' Open Source Workbook (No variable,but it is the active one).
Workbooks.Open Filename:=srcName
' Define Source Worksheet ('wsSource').
Dim wsSource As Worksheet
Set wsSource = ActiveWorkbook.Worksheets("Sheet1") ' Note the double quotes.
' Define Destination Worksheet ('wsDest')
Dim wsDest As Worksheet
Set wsDest = wb.Worksheets("Sheet1") ' Note the double quotes...
' ... and not: Set wsDest = Workbooks(wb).Worksheets("Sheet1") - wrong!
' Define Source Last (Non-Empty) Row ('srcLastRow').
Dim srcLastRow As Long
srcLastRow = wsSource.Cells(wsSource.Rows.Count,"A").End(xlUp).Row
' Define Destination First (Empty (available)) Row ('destFirstRow').
Dim destFirstRow As Long
destFirstRow = wsDest.Cells(wsDest.Rows.Count,"A").End(xlUp).Offset(1).Row
' Copy from Source to Destination.
wsSource.Range("A2:A" & srcLastRow).Copy wsDest.Range("A" & destFirstRow)
' Note "A2:A" and not: "A2" - wrong!
' Now you wanna close the Source Workbook,but how?
' You can use the 'Parent' property:
wsSource.Parent.Close False ' False means not to save changes.
' If you closed,wsDest is active again so you don't need:
'wsDest.Activate
' Inform user,so you know the code has finished.
MsgBox "Copied data.",vbInformation,"Success"
ProcExit:
Exit Sub
clearError:
Debug.Print "'" & ProcName & "': " & vbLf _
& " " & "Run-time error '" & Err.Number & "':" & vbLf _
& " " & Err.Description
On Error GoTo 0 ' Turn off error trapping.
GoTo ProcExit
End Sub
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