将目录中的文件列表转换为列表，以便可以被执行-python

如何解决将目录中的文件列表转换为列表，以便可以被执行-python

因此，我想创建一个目录列表，以便对其进行迭代。 目的是使函数能够查看列表并在每一行上运行该函数。 这就是我所做的：

import re
import os
import json

#this is what should search a list all files in directory
def list_of_files():
    path = '/mnt/c/Users/deni/desktop/chatette/'
    files = os.listdir(path)
    for f in files:
        print(f)
        return(f)


#this is where the file is loaded
def load_file(filename):
    loadfile = open("filename,"r")
    replace_name = os.path.basename(loadfile.name)
    name_of_file = os.path.splitext(replace_name)[0]

    if loadfile.mode == 'r':
        contents = loadfile.read()
        remove_dashes = re.sub("-","",contents)
        remove_hashes =re.sub("##",remove_dashes)
        remove_intent =re.sub("intent",remove_hashes)
        remove_colan =re.sub(":",remove_intent)
        remove_generic =re.sub("Generic",remove_colan)
        remove_critical =re.sub("critical",remove_generic)
        remove_line_one=re.sub("<! Generated using Chatette v1.6.2 >",name_of_file,remove_critical)
        edited_contents = remove_line_one   
        #print(edited_contents)
        return(edited_contents)

#this is suppose to iterate the file and run the function for each file listed
listoffile = list_of_files()

for txt in listoffile:
    for i in list_of_files():
        if i.endswith(".xlsx"):
            load_file(txt)

这是我得到的回应

Traceback (most recent call last):
  File "generate.py",line 68,in <module>
    for txt in listoffile:
TypeError: 'nonetype' object is not iterable

您能帮我吗？

解决方法

我可以想到两种选择：

• 返回文件列表
• 使用生成器一次返回一个文件

我将从第一个开始，因为它更容易实现：

def list_of_files():
    path = '/mnt/c/Users/deni/desktop/chatette/'
    return os.listdir(path)

#...
listoffile = list_of_files()

for txt in listoffile:
    if i.endswith(".xlsx"):
        load_file(txt)

第二个在内存使用方面更为理想，因为它不会在返回前预先分配文件列表：

def list_of_files():
    path = '/mnt/c/Users/deni/desktop/chatette/'
    files = os.listdir(path)
    for f in files:
        print(f)
        yield f
#...
listoffile = list_of_files()

for txt in listoffile:
    if i.endswith(".xlsx"):
        load_file(txt)

,

在“ list_of_files”函数的for循环中，您仅通过1条路径进行迭代即可返回。然后打印并返回该路径。

在循环结束后，您需要返回“文件”而不是“ f”。

def list_of_files():
    path = '/mnt/c/Users/deni/desktop/chatette/'
    files = os.listdir(path)
    for f in files:
        print(f)
        return(f)

所以它必须是

def list_of_files():
    path = '/mnt/c/Users/deni/desktop/chatette/'
    files = os.listdir(path)
    for f in files:
        print(f)
    return(files)

,

查看堆栈跟踪：

 Puppeteer script is working (headless:false) ....
 Captcha appears on my chromium screen
 I solve it manually and the next screen appears (Which would happen if there were no captcha)
 Help=> Puppeteer picks up the "current" (post-captcha) page and continues execution....

我们看到问题是Traceback (most recent call last): File "generate.py",line 68,in <module> for txt in listoffile: TypeError: 'NoneType' object is not iterable ，也就是说for txt in listoffile:是listoffile

这意味着None返回None。我最好的猜测是您发布的目录中没有文件：list_of_files()

您可能还希望'/mnt/c/Users/deni/desktop/chatette/'到list_of_files()，而不是循环内的单个文件。