如何解决找到标准偏差函数
我以为我已经完成了我的功能,但事实证明它不能按我预期的那样工作。应该计算一个数字数组的标准偏差值。
function average (arr) {
let result = 0
for (let counter = 0; counter < arr.length; counter++) {
result += arr[counter]
}
const averageValue = result / arr.length
return averageValue
}
function standardDeviation (arr) {
if (arr.length === 1) {
return 0
} else {
const getAverage = arr.map(x => average(arr) - x)
const squaredArr = getAverage.map(i => i * i)
let sum = squaredArr.reduce(function (i,j) {
return i + j
})
const dividedArr = sum / (arr.length - 1)
return Math.sqrt(dividedArr)
}
}
如果我传递数组[4、2、6、1、3、7、5、3],则我的函数应返回1.8998,但返回2.031 .....为什么?以及如何解决该问题?
解决方法
不需要average
函数,可以通过以下几行轻松更改它:
// instead of
const getAverage = arr.map(x => average(arr) - x)
// calculate average
let arrSum = arr.reduce(function (i,j) {
return i + j
});
let getAverage = arr.map(x => arrSum/arr.length - x);
...
// also this was changed
const dividedArr = sum / (arr.length - 1)
// with this
let dividedArr = sumsQuaredArr / arr.length;
您可以检查以下示例。控制台中提供了部分输出,可轻松检查功能的每个步骤。
编辑:您的示例数组已添加用于测试。
const arr = [30,28,45,33,34,10,13,19];
const arr2 = [4,2,6,1,3,7,5,3];
function standardDeviation (arr) {
if (arr.length === 1) {
return 0;
}
console.log("InitialArray ",arr);
let arrSum = arr.reduce(function (i,j) {
return i + j
});
console.log("Average ",arrSum/arr.length);
let getAverage = arr.map(x => arrSum/arr.length - x);
console.log("getAverage ",getAverage);
let squaredArr = getAverage.map(i => i * i);
console.log("squaredArr ",squaredArr );
let sumsQuaredArr = squaredArr.reduce(function (i,j) {
return i + j
});
console.log("sumsQuaredArr ",sumsQuaredArr );
let dividedArr = sumsQuaredArr / arr.length;
console.log("dividedArr ",dividedArr );
return Math.sqrt(dividedArr);
}
console.log("standardDeviation ",standardDeviation (arr));
console.log("standardDeviation ",standardDeviation (arr2));
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