如何解决具有限制的Graphql-ruby分页会生成n + 1个查询
想象一下,您拥有某项的用户和订阅。您需要对用户的订阅进行分页。每个用户都有不同数量的订阅。这是我想到的第一件事:
users = User.where(id:[array]).index_by(&:id) # find users and make an object with id as a key
subs = Subs.where(user_id: [array]).limit(3).offset(1) # find subs for all users what we need
subs.forEach{|s| users[s[:id]].subs << s} # build graphql response
但是它不起作用,因为它通常限制所有用户,但我们需要每个用户。 输出应如下所示:
{
users: [
{
id: 1,subs: [sub1,sub2] // this user has only two elements and it's like an end of pagination
},{
id: 2,subs: [sub3,sub4,sub5] // this user has more items on next page
}
]
}
Graphql默认情况下为每个用户进行子查询以使其真实,但n + 1。有没有什么方法可以使它在没有n + 1的情况下并通过cpu和内存使用进行优化?
解决方法
在这里解决https://elixirforum.com/t/how-to-do-pagination-in-a-nested-graphql-query-with-dataloader-batch-load/25282也许对某人有帮助。这样的查询应该带有分区。
def query(queryable,params) do
case params do
%{chapters: true,offset: offset,first: first} ->
last = offset + first
query = from r in queryable,select: r,select_merge: %{chapter_number: fragment("row_number() over (PARTITION by parent_id order by \"name\")")}
from r in subquery(query),select: %Wikisource.Book{id: r.id,name: r.name,info: r.info,preface: r.preface,info_html: r.info_html,preface_html: r.preface_html},where: r.chapter_number >= ^offset and r.chapter_number < ^last
%{order_by: order_by,offset: from,first: size} -> from record in queryable,order_by: ^order_by,offset: ^from,limit: ^size
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。