如何解决“名称不匹配”打印,但在此打印5次
当我键入数组列表中没有的内容时,“名称不匹配”将打印5次。我只想打印一次。
public class Arrays {
public static void main(String[] args) {
String[] names = {"Meisam","Raju","Sasi","Aju","Ram"};
int[] numbers = {123456,654321,345678,953456,123445};
for (int i = 0; i < names.length; i++) {
System.out.println(names[i]);
}
System.out.println("Please Enter a Name: ");
Scanner scanner = new Scanner(system.in);
String name = scanner.next();
for(int i = 0; i < names.length; i++){
if(name.equals(names[i])) {
System.out.println(numbers[i]);
} else {
System.out.println("Names Doesn't Match!");
}
}
}
}
输出为:
Meisam
Raju
Sasi
Aju
Ram
Please Enter a Name:
raj //input a keyword called 'raj'
Names Doesn't Match!
Names Doesn't Match!
Names Doesn't Match!
Names Doesn't Match!
Names Doesn't Match!
解决方法
哪一行代码使“名称不匹配”打印5次?
for(int i = 0; i < names.length; i++) {
// ...
}
它将为数组中的每个元素打印Names Doesn't Match!
。如果数组包含例如10个元素,那么您将看到10次此消息。
如何仅打印1次“名称不匹配”?
只需首先检查整个数组,然后在是否找到名称的地方设置a marker
。只有在此之后,maker is false
才打印消息。
int j = -1; // j == -1 -> means NOT_FOUND
for (int i = 0; i < name.length(); i++) {
if (name.equals(names[i])) {
j = i;
break;
}
}
System.out.println(j == -1 ? "Names Doesn't Match!" : numbers[j]);
对于此问题,我认为最好使用Map
:
public static void main(String... args) {
Map<String,Integer> nameNumber = Map.of(
"Meisam",123456,"Raju",654321,"Sasi",345678,"Aju",953456,"Ram",123445);
nameNumber.keySet().forEach(System.out::println);
System.out.print("Please Enter a Name: ");
String name = new Scanner(System.in).next();
Integer number = nameNumber.get(name);
System.out.println(number == null ? "Names Doesn't Match!" : number);
}
,
更改代码以设置一个布尔值,并在循环后对其求值。
此外,您可以在发现循环后立即退出循环。
boolean found = false;
for(int i = 0; i < names.length; i++){
if(name.equals(names[i])) {
System.out.println(numbers[i]);
found = true;
break;
}
}
if (!found){
System.out.println("Names Doesn't Match!");
}
,
删除for循环中的其他部分 添加System.exit(0); for循环中if块内部的最后一行 添加System.out.println(“名称不匹配!”);在for循环之后
,for(int i = 0; i < names.length; i++) {
if(name.equals(names[i])) {
System.out.println(numbers[i]);
} else {
System.out.println("Names Doesn't Match!");
}
}
使您的代码将字符串打印5次。这样做是因为您要遍历names
数组的所有5个元素。
我建议,如果要打印一次,可以将其放入函数中,并在返回"Names Doesn't Match!
时返回匹配的结果
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