如何解决使用UIPanGestureRecognizer获取视图的翻译-Swift-以编程方式
我正在使用UIPanGestureRecognizer方法转换视图:
@objc fileprivate func handlePan(_ gestureRecognizer : UIPanGestureRecognizer){
if gestureRecognizer.state == .began || gestureRecognizer.state == .changed {
makedisappearButtons()
deleteBox.isHidden = false
let translation = gestureRecognizer.translation(in: self.view)
// note: 'view' is optional and need to be unwrapped
gestureRecognizer.view!.center = CGPoint(x: gestureRecognizer.view!.center.x + translation.x,y: gestureRecognizer.view!.center.y + translation.y)
gestureRecognizer.setTranslation(CGPoint.zero,in: self.view)
if gestureRecognizer.view!.frame.intersects(deleteBox.frame) {
UIView.animate(withDuration: 0.3,delay: 0,options: .curveEaseInOut,animations: {
gestureRecognizer.view!.transform = .init(scaleX: 0.6,y: 0.6)
self.deleteBox.transform = .init(scaleX: 1.2,y: 1.2)
},completion: nil)
} else {
gestureRecognizer.view!.setNeedsdisplay()
gestureRecognizer.setTranslation(.zero,in: self.view)
UIView.animate(withDuration: 0.3,animations: {
self.deleteBox.transform = .identity
gestureRecognizer.view!.transform = .identity
},completion: nil)
}
}
if gestureRecognizer.state == .ended {
makeButtonsReAppear()
if gestureRecognizer.view!.frame.intersects(deleteBox.frame) {
gestureRecognizer.view!.isHidden = true
gestureRecognizer.view?.removeFromSuperview()
} else {
gestureRecognizer.view!.setNeedsdisplay()
gestureRecognizer.setTranslation(.zero,in: self.view)
gestureRecognizer.view!.transform = .identity
}
print(gestureRecognizer.translation(in: self.view))
deleteBox.isHidden = true
}
}
我想知道gestureRecognizer.state ==中视图的翻译。但是当我尝试打印视图时,它是x:0,y:0。
解决方法
每次手势处理程序调用{{1}}时,您都将转换回.zero
。
changed
但是,当手指抬起时,状态会更改为gestureRecognizer.setTranslation(.zero,in: self.view)
,而此时的平移不再改变。
documentation说:
当用户的手指从屏幕上抬起时,手势识别器进入UIGestureRecognizer.State.ended状态。
因此翻译与上次ended
调用和 changed
的相同相同-并且因为您已经设置了框架ended
中的gestureRecognizer.view
中,您无需在changed
内部进行任何操作。
可以从哪里调用此方法,然后将其放在viewDidAppear中并尝试。否则,请调用setNeedsDisplay和LayoutIfNeeded方法。
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