寻求正确的MySql“ IF”方法的指南 表结构所需结果有效但“肮脏”的解决方案

如何解决寻求正确的MySql“ IF”方法的指南 表结构所需结果有效但“肮脏”的解决方案

我需要获取特定列值上的数据，但还需要包含已启用IF并且inventory大于0的项目stock。

以下仅是一个概念查询，可以直观地看到我的意图。当然不行。

SELECT id,name,image,price
FROM shop
WHERE published = 1
AND price > 2
  /*concept clause here*/
    IF(inventory = 1 AND stock > 0,include,ignore)
  /*end concept*/
ORDER BY RAND() 
LIMIT 30

表结构

shop
__________________________________________
|id|name  |image   |price|inventory|stock|
------------------------------------------
|4 |widget|pic.jpg |6    |1        |12   |
------------------------------------------
|5 |bolt  |bolt.jpg|7    |0        |0    |
------------------------------------------
|6 |trowel|trow.jpg|12   |1        |0    |
__________________________________________

所需结果

数组

[
    ['id'=>4,'name'=>'widget','image'=>'pic.jpg','price'=>6],['id'=>5,'name'=>'bolt','image'=>'bolt.jpg','price'=>7]
]

启用了inventory但stock值为0的行将不出现在数组中。

如何根据这种情况获得结果？

---

有效但“肮脏”的解决方案

我已经运行了两次类似的查询，然后合并数组

获取未启用库存的商品

SELECT id,price
FROM shop
WHERE published = 1
AND price > 2
AND inventory = 0 
ORDER BY RAND() 
LIMIT 30

获取已启用库存且有库存的物品

SELECT id,price
FROM shop
WHERE published = 1
AND price > 2
AND inventory = 1 
AND stock > 0 
ORDER BY RAND() 
LIMIT 30

合并数组

$merged = array_merge($withoutInventory,$withInventory);

解决方法

样本数据和预期结果将有助于澄清。我认为您需要将列选择和/或它们括起来

SELECT id,name,image,price
FROM shop
WHERE (published = 1 AND price > 2) OR
      (inventory = 1 AND stock > 0)
ORDER BY RAND() 
LIMIT 30