如何解决cquery没有匹配的功能来调用'to_upper'
#include <iostream>
#include <string>
#include <boost/algorithm/string.hpp>
using namespace std;
int main() {
string city1,city2;
cout << ("Please enter your citys name");
cin >> city1;
cout << ("Please enter your citys second name");
cin >> city2;
cout << city1 [0,1,2,3,4];
cout << city2 [0,4];
boost::to_upper(city1,city2);
cout << city1,city2;
}
这是我的代码,出于某种原因boost :: to_upper(city1,city2);收到错误:[cquery]调用“ to_upper”没有匹配的功能
解决方法
boost::algorithm::to_upper
被声明为(来自boost reference)
template<typename WritableRangeT>
void to_upper(WritableRangeT & Input,const std::locale & Loc = std::locale());
,因此您只能将一个字符串传递给此函数。更换
boost::to_upper(city1,city2);
使用
boost::to_upper(city1);
boost::to_upper(city2);
使代码编译,示例输出为Please enter your citys namePlease enter your citys second nameosLONDON
。
它缺少换行符,还有一个错误-对逗号运算符的误解。通常,逗号用于分隔参数或数组元素,但以行分隔
cout << city1 [0,1,2,3,4];
cout << city2 [0,4];
// ...
cout << city1,city2;
使用逗号运算符。逗号运算符采用两个操作数,其值是右操作数的值(例如int x = (1,2);
变量x
等于2之后)。上面的代码等同于
cout << city1[4];
cout << city2[4];
// ...
cout << city1;
city2;
最后,正确的代码是
#include <iostream>
#include <string>
#include <boost/algorithm/string.hpp>
using namespace std;
int main() {
string city1,city2;
cout << "Please enter your citys name" << std::endl;
cin >> city1;
cout << "Please enter your citys second name" << std::endl;
cin >> city2;
cout << city1 << std::endl;
cout << city2 << std::endl;
boost::to_upper(city1);
boost::to_upper(city2);
cout << city1 << std::endl << city2 << std::endl;
}
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