如何解决在Javascript / Jquery
我想以编程方式旋转Inkscape中设计为SVG的时钟的指针，以使用Javascript / Jquery在浏览器中创建自定义设计的日期/时间选择器。
SVG：
<svg
width="2200"
height="1700"
viewBox="0 0 582.08332 449.79166"
sodipodi:docname="DateTimePicker.svg">
...
<g
inkscape:label="DateTimePicker"
inkscape:groupmode="layer"
id="layer1"
transform="translate(0,152.79168)">
<g
id="g4802"
inkscape:label="SecondsHand"
inkscape:transform-center-x="0.23194686"
inkscape:transform-center-y="-22.707409"
transform="translate(10.583327,-42.333328)">
.... (There are some paths in here to draw the shape)
</g>
<g
id="g4798"
inkscape:label="MinutesHand"
inkscape:transform-center-x="0.050484234"
inkscape:transform-center-y="-20.583753"
transform="translate(10.583352,-42.333325)">
.... (There are some paths in here to draw the shape)
</g>
<g
id="g4789"
inkscape:label="HoursHand"
inkscape:transform-center-x="-0.29101068"
inkscape:transform-center-y="-12.194587"
transform="translate(10.583295,-42.333339)">
<path
inkscape:transform-center-y="-12.335484"
sodipodi:nodetypes="ccccccccc"
inkscape:transform-center-x="-0.43053568"
inkscape:connector-curvature="0"
id="path3199"
d="m 424.77397,-31.058733 -2.7993,21.043385 c 0,0 -0.41499,2.6995795 0.88985,4.0317895 -0.089,0.23193 -0.1351,0.47814 -0.13589,0.72657 -1.3e-4,1.12967 0.91567,2.04548 2.04534,2.04536 1.12947,-1.6e-4 2.04496,-0.91589 2.04483,-2.04536 -1.8e-4,-0.24869 -0.0457,-0.49525 -0.13436,-0.7276 1.3035,-1.33258 0.88834,-4.0307595 0.88834,-4.0307595 z"
style="opacity:0.778;fill:#000000;fill-opacity:1;stroke:none;stroke-width:0.30000001;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1;filter:url(#filter2507)"
inkscape:label="ShadowHourHand" />
<g
inkscape:transform-center-x="5.3889177e-06"
transform="translate(47.709026,-125.85737)"
inkscape:transform-center-y="-10.8713"
id="g3193"
inkscape:label="HourHand">
<path
sodipodi:nodetypes="ccccccccc"
inkscape:connector-curvature="0"
id="path3183"
d="m 1423.707,324.97033 -10.58,72.17225 c 0,0 -1.5685,10.20314 3.3632,15.23828 -0.3366,0.87657 -0.5106,1.80713 -0.5136,2.74609 -5e-4,4.26959 3.4608,7.73091 7.7304,7.73047 4.2688,-6.1e-4 7.729,-3.46162 7.7285,-7.73047 -7e-4,-0.93992 -0.1727,-1.87183 -0.5078,-2.75 4.9266,-5.03651 3.3575,-15.23437 3.3575,-15.23437 z"
style="opacity:1;fill:url(#linearGradient4836);fill-opacity:1;stroke:none;stroke-width:1.13385832;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1"
transform="matrix(0.26458333,0.26458333,11.249983)" />
<path
sodipodi:nodetypes="ccccccccccc"
inkscape:connector-curvature="0"
id="path3185"
transform="matrix(0.26458333,11.249983)"
d="m 1423.8672,338.32229 -6.9727,63.97654 0.2422,0.002 v 0.0215 c 8e-4,4.63516 3.1214,8.3923 6.9707,8.39257 3.8145,-0.002 6.919,-3.6962 6.9668,-8.28906 h 0.033 l -0.047,-0.67969 v -0.0176 -0.0215 z"
style="opacity:0.7;fill:#ffe25d;fill-opacity:1;stroke:none;stroke-width:1.13385832;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1;filter:url(#filter3111)" />
<path
inkscape:connector-curvature="0"
id="circle3187"
d="m 378.15497,121.08581 a 1.4660022,1.4660022 0 0 1 -1.46601,1.466 1.4660022,1.4660022 0 0 1 -1.466,-1.466 1.4660022,1.4660022 0 0 1 1.466,1.4660022 0 0 1 1.46601,1.466 z"
style="opacity:1;fill:#ffe56a;fill-opacity:1;stroke:none;stroke-width:0.30000001;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1;filter:url(#filter2836)" />
<path
sodipodi:nodetypes="scscs"
inkscape:connector-curvature="0"
id="path3189"
d="m 377.65184,117.39486 c 0,0.83592 -0.41881,1.51358 -0.93544,1.51358 -0.51663,0 -0.93544,-0.67766 -0.93544,-1.51358 0,-0.83592 0.35199,-2.54925 0.86862,-2.54925 0.51663,0 1.00226,1.71333 1.00226,2.54925 z"
style="opacity:0.70899999;fill:#ffffff;fill-opacity:1;stroke:none;stroke-width:0.30000001;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1;filter:url(#filter3146)" />
<path
inkscape:connector-curvature="0"
id="circle3191"
d="m 377.173,121.08581 a 0.48403955,0.48403955 0 0 1 -0.48404,0.48404 0.48403955,0.48403955 0 0 1 -0.48403,-0.48404 0.48403955,0.48403955 0 0 1 0.48403,0.48403955 0 0 1 0.48404,0.48404 z"
style="opacity:1;fill:#ffffff;fill-opacity:1;stroke:none;stroke-width:0.30000001;stroke-miterlimit:4;stroke-dasharray:none;stroke-opacity:1;filter:url(#filter3168)" />
</g>
</g>
</g>'s as needed
Inkscape在HoursHand上以15度的旋转增量计算得出的结果。
{
// 0 degrees
transform-center: (-0.29101049,-12.194589),transform: translate(10.583294,-42.333341)
},{
transform-center: (-2.679194,-11.668645),transform: rotate(15,590.36335,14.32942)
},{
transform-center: (-5.8379232,-10.278138),transform: rotate(30,508.58162,-6.1159341)
},{
transform-center: (-8.5291975,-8.1175788),transform: rotate(45,480.68739,-13.089463)
},{
transform-center: (-10.569195,-5.2923862),transform: rotate(60,466.24828,-16.699228)
},{
transform-center: (-11.819306,-1.9982106),transform: rotate(75,457.17147,-18.968421)
},{
transform-center: (-12.194588,0.29100973),transform: rotate(90,450.7532,-20.572983)
},{
transform-center: (-11.668649,2.679191),transform: rotate(105,445.82829,-21.804206)
},{
transform-center: (-10.278149,5.8379174),transform: rotate(120,441.80712,-22.809495)
},{
transform-center: (-8.1175958,8.5291943),transform: rotate(135,438.35406,-23.672756)
},{
transform-center: (-5.292401,10.569196),transform: rotate(150,435.25813,-24.446734)
},{
transform-center: (-1.9982232,11.819314),transform: rotate(165,432.37318,-25.167967)
},{
transform-center: (0.2910098,12.194597),transform: rotate(180,429.58653,-25.864625)
},{
transform-center: (2.6792046,11.668654)
transform: rotate(-165,426.79988,-26.561283)
},{
transform-center: (5.837939,10.278141),transform: rotate(-150,423.91493,-27.282518)
},{
transform-center: (8.1175808,8.5292134),transform: rotate(-135,420.819,-28.056498)
},{
transform-center: (10.569206,5.293819),transform: rotate(-120,417.36594,-28.919761)
},{
transform-center: (11.819324,1.9982024),transform: rotate(-105,413.34476,-29.925051)
},{
transform-center: (12.194597,-0.29101935),transform: rotate(-90,408.41985,-31.156276)
},{
transform-center: (11.668649,-2.6792024),transform: rotate(-75,402.00158,-32.760839)
},{
transform-center: (10.278139,-5.8379339),transform: rotate(-60,392.92477,-35.030033)
},{
transform-center: (8.1175801,-8.5292112),transform: rotate(-45,378.48565,-38.6398)
},{
transform-center: (5.2923805,-10.569206),transform: rotate(-30,350.59142,-45.613334)
},{
transform-center: (1.9982049,-11.819318),transform: rotate(-15,268.80967,-66.058702)
}
以下是我在HoursHand上0度运行的一些Javascript：
CTM: SVGMatrix
a: 0.6871868371963501
b: 0
c: 0
d: 0.6871868371963501
e: 7.272700786590576
f: 76.36006927490234
boundingBox: SVGRect
height: 28.33203125
width: 6.1015625
x: 421.53515625
y: -31.05859375
boundingClientRect: DOMRect
bottom: 74.5
height: 19.5
left: 296.933349609375
right: 301.15000915527344
top: 55
width: 4.2166595458984375
x: 296.933349609375
y: 55
0: <g id="g4789" inkscape:label="HoursHand" inkscape:transform-center-x="-0.29101068" inkscape:transform-center-y="-12.194587" transform="translate(10.583295,-42.333339)">
screenCTM: SVGMatrix
a: 0.6871868371963501
b: 0
c: 0
d: 0.6871868371963501
e: 7.272700786590576
f: 76.36006927490234
transform: "translate(10.583295,-42.333339)"
transform_center_x: "-0.29101068"
transform_center_y: "-12.194587"
逆CTM =（a，d = 1.45522，b，c = 0，e = -10.58339，f = -111.12089）
我想知道的是从HoursHand以及任何度数或旋转数开始的任意对象，为此如何计算变换中心的x和y以及旋转中心的x和y Inkscape计算出来的度数。
注意：这里的变换中心不在中心，我想使用Javascript而不是依靠CSS，因为SVG变换的处理方式与CSS变换的处理方式不同，所以此处说明的方法将不起作用：SVG Animation rotate group around its center
更新1：我已经阅读了有关此答案中提到的相关章节的内容：Why am I failing to rotate a path around a given point in SVG指向此文本：https://www.w3.org/TR/SVG/coords.html#TransformProperty，这对某些人有所帮助。
这里的问题是，我从Inkscape出来的路径在其用户坐标空间中具有m 424.77397，-31.058733之类的坐标。如果您注意到，在HoursHand旋转15度时，我旋转了（15,14.32942），在旋转30度时，我旋转了（30,508.58162，-6.1159341），变换的旋转中心在x轴上发生了巨大变化。 / p>
因此，需要使用一些角度查找代码来预先确定旋转时旋转中心应位于哪里，而不是当前用户坐标空间中的translate（〜10，〜-42）。需要帮助。
解决方法
在Inkscape中执行此操作的明智方法是选择一个具有“变换：translate（x，y）”属性的组节点，然后删除该变换。然后选择组的子节点并在组节点需要的位置定位。在Javascript方面，我需要记住旋转之前转换的中心点位置。时针，分针和秒针都共享相同的旋转中心点，该中心点必须相对于通过getBBox（）获得的边界框坐标绝对定位。
在某些情况下，知道在SVG用户坐标系中如何进行旋转（具有平移且转换中心偏心的组）的旋转仍可能是有利的。
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