如何解决根据其他2台摄像机的校准输出计算第三台摄像机中的3D点
我从三个不同的天使那里进行了一次心理治疗会议:
- 摄像机1专注于患者
- cam 2专注于治疗师
- cam 3从侧面同时捕捉
我用Matlab校准工具校准了cam1和cam2,并对带cam1的cam3和带cam2的cam3进行了外部立体声校准,并且获得了所有会话的所有旋转矢量和本征矩阵。
现在,给定2个点(来自cam1 / 2),我感兴趣的是计算“真实世界” cam3中的3D点(我使用校准矩阵从两个相机的每个点绘制的矢量之间的交点,较早发现)。
我用python编写了这段代码以找到3D点:
'''
External calibration output between 2 cameras:
---------------------------------------------
R - Rotation Matrix of camera one relative to camera two
O - Translation vector of camera one relative to camera two
Anotations:
---------
org - of camera which represents the real world (with origin [0,0])
rel - of relative camera with translation vector
d - direction vector of each camera,i.e,np.linalg.inv(K).dot([u,v,1])
[u,v] - pixel in the image
K - Calibration matrix (the intrinsicMatrix)
Output:
------
3D point of each camera
'''
def find3DPoints (d_org,O_org,d_rel,R_rel,O_rel):
dist = 1000
alpha=0
beta=0
X_org=0
X_rel=0
d_rel = np.matmul(np.linalg.inv(R_rel),d_rel)
while (dist > 10) :
alpha = np.random.randint(200)
beta = np.random.randint(200)
#print("alpha: ",alpha)
#print("beta: ",beta)
X_org = alpha*d_org + O_org
X_rel = beta*d_rel + O_rel
dist = np.linalg.norm(X_org-X_rel)
#print("distance: ",dist)
print("distance between 2 closest points: ",dist)
print("alpha: ",alpha)
print("beta: ",beta)
print("X Origin: ",X_org)
print("X Relative: ",X_rel)
return X_org,X_rel
我得到的结果令人满意:
distance between 2 closest points: 8.663262014946904
alpha: 140
beta: 81
X Origin: [-41.49543898 11.50037104 140. ]
X Relative: [-41.69268956 3.02469031 141.78214397]
然后,我尝试编写一种更好的解决方案,该解决方案使用线性代数使用最小二乘(Ax = b)查找alpha和beta:
我之所以这样想,是因为:
X = O_org + alpha * d_org
X = O_rel + beta * d_rel
===>
[d_rel,d_org] * [-beta,alpha] = O_rel-O_org
[d_rel,d_org] => 3x2矩阵
O_rel-O_org => 3x1向量
def find3DPointByLeastSquare(d_org,O_rel):
A=np.array([d_org,d_rel])
#print("A=",A)
b=O_rel-O_org
#b=np.array(O_org)-O_rel
#print("b=",y)
# Ax=b
alpha,beta = np.linalg.lstsq(A.T,b,rcond=None)[0]
#beta=-beta
print("alpha: ",alpha)
print("beta: ",beta)
X_org = O_org + alpha*d_org
print("X Origin=",X_org)
X_rel = O_rel + -beta*d_rel
print("X Relative=",X_rel)
return X_org,X_rel
但是我得到的结果与第一个解决方案不同!!! 我期望得到相同的结果。可能是什么原因?
alpha: 199.83226356812804
beta: -204.61307546220422
X Origin= [ 27.31677265 16.63486267 199.83226357]
X Relative= [ 67.03447507 -28.86206184 198.19026467]
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