我的订购词典无法正常运行

如何解决我的订购词典无法正常运行

所以基本上我有以下代码：

from collections import OrderedDict as OD
person = OD({})

for num in range(10):
    person[num] = float(input())

tall = max(person.values())
short = min(person.values())

key_tall = max(person.keys())
key_short = min(person.keys())

print(f'The shortest person is the person number {key_short} who is {short}meters tall')
print(f'The tallest person is the person number {key_tall} who is {tall}meters tall')

理论上，当我在字典上放10个人时，它是第一个数字1，一直到9，最后一个数字是0，输出应该是：

The shortest person is the person number 9 who is 0.0m meters tall
The tallest person is the person number 8 who is 9.0m meters tall

但实际上它会打印：

The shortest person is the person number 0 who is 0.0m meters tall
The tallest person is the person number 9 who is 9.0m meters tall

由于某种原因，当我的字典的值从1一直增长到10时，它可以正常工作。

关于这种情况为什么发生以及如何解决的任何想法？

解决方法

key_tall = max(person.keys())
key_short = min(person.keys())

您的键是整数0..9，因此，由于您要查询的是这两个值，因此您期望分别获得9和0最小/最大键，而与值无关。

您似乎要紧随拥有最高/最低价值的人的钥匙，但这不是该代码所提供的。

如果您追随具有最大值的项目的索引，则可以执行以下操作：

indexes_tall = [idx for idx in range(len(person)) if person[idx] == max(person.keys())]

这将为您提供与最大值匹配的索引列表，然后您可以根据需要对其进行处理。举一个例子：

from collections import OrderedDict as OD
person = OD({})

for num in range(10):
    person[num] = float((num + 1) % 10) # effectively your input

tall = max(person.values())
short = min(person.values())

keys_tall = [str(idx + 1) for idx in range(len(person)) if person[idx] == max(person.keys())]
keys_short = [str(idx + 1) for idx in range(len(person)) if person[idx] == min(person.keys())]

print(f'The shortest height of {short}m is held by: {" ".join(keys_short)}')
print(f'The tallest height of {tall}m is held by: {" ".join(keys_tall)}')

会给您：

The shortest height of 0.0m is held by: 10
The tallest height of 9.0m is held by: 9