如何解决令牌化字符串,Java中每个令牌的字符数
我试图弄清楚是否可以计算每个令牌的字符并显示以下信息:
day被标记,我的输出将是:“ Day有3个字符。”并继续对每个令牌进行操作。
我最后一次打印出每个令牌中的字符数的循环永远不会打印:
public static void main(String[] args) {
Scanner sc = new Scanner(system.in);
ArrayList<String> tokenizedInput = new ArrayList<>();
String sentenceRetrieved;
// getting the sentence from the user
System.out.println("Please type a sentence containing at least 4 words,with a maximum of 8 words: ");
sentenceRetrieved = sc.nextLine();
StringTokenizer strTokenizer = new StringTokenizer(sentenceRetrieved);
// checking to ensure the string has 4-8 words
while (strTokenizer.hasMoretokens()) {
if (strTokenizer.countTokens() > 8) {
System.out.println("Please re-enter a sentence with at least 4 words,and a maximum of 8");
break;
} else {
while (strTokenizer.hasMoretokens()) {
tokenizedInput.add(strTokenizer.nextToken());
}
System.out.println("Thank you.");
break;
}
}
// printing out the sentence
System.out.println("You entered: ");
System.out.println(sentenceRetrieved);
// print out each word given
System.out.println("Each word in your sentence is: " + tokenizedInput);
// count the characters in each word
// doesn't seem to run
int totalLength = 0;
while (strTokenizer.hasMoretokens()) {
String token;
token = sentenceRetrieved;
token = strTokenizer.nextToken();
totalLength += token.length();
System.out.println("Word: " + token + " Length:" + token.length());
}
}
}
控制台示例:
请输入至少包含4个单词,最多8个单词的句子:
你好,这是一个测试
谢谢。
您输入了:
你好,这是一个测试
句子中的每个单词都是:[你好,这就是一个测试]
解决方法
首先,我添加了必要的导入并围绕此main方法构建了一个类。这应该编译。
import java.util.ArrayList;
import java.util.Scanner;
import java.util.StringTokenizer;
public class SOQ_20200913_1
{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
ArrayList<String> tokenizedInput = new ArrayList<>();
String sentenceRetrieved;
// getting the sentence from the user
System.out.println("Please type a sentence containing at least 4 words,with a maximum of 8 words: ");
sentenceRetrieved = sc.nextLine();
StringTokenizer strTokenizer = new StringTokenizer(sentenceRetrieved);
// checking to ensure the string has 4-8 words
while (strTokenizer.hasMoreTokens()) {
if (strTokenizer.countTokens() > 8) {
System.out.println("Please re-enter a sentence with at least 4 words,and a maximum of 8");
break;
} else {
while (strTokenizer.hasMoreTokens()) {
tokenizedInput.add(strTokenizer.nextToken());
}
System.out.println("Thank you.");
break;
}
}
// printing out the sentence
System.out.println("You entered: ");
System.out.println(sentenceRetrieved);
// print out each word given
System.out.println("Each word in your sentence is: " + tokenizedInput);
// count the characters in each word
// doesn't seem to run
int totalLength = 0;
while (strTokenizer.hasMoreTokens()) {
String token;
token = sentenceRetrieved;
token = strTokenizer.nextToken();
totalLength += token.length();
System.out.println("Word: " + token + " Length:" + token.length());
}
}
}
接下来,让我们看一下这个工作示例。看起来直到最后一个while循环(计算字符长度的循环)之前的所有东西都工作正常。但是,如果您注意到,最后一个循环之前的while循环将继续循环,直到没有更多令牌可供提取为止。因此,在完成所有令牌的收集并且没有更多令牌可以收集之后,您尝试创建最终的while循环,要求它收集更多令牌。直到它用完了要收集的令牌之前,它才可能到达while循环!
最后,为了解决这个问题,您可以简单地遍历倒数第二个while循环中添加到的列表,并循环遍历最后一个循环!
例如:
int totalLength = 0;
for (String each : tokenizedInput) {
totalLength += each.length();
System.out.println("Word: " + each + " Length:" + each.length());
}
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