如何解决基本的python类和大型if语句
尝试为作业做一些代码。希望我们以每小时最快的速度打印汽车品牌的名称。但是,为了找出最快的速度,老师希望我们做大量的if陈述来找出答案。
class carspeed:
def __init__ (self,distance,time):
self.distance=distance
self.time=time
def cspeed(self):
return (self.distance)//(self.time)
Ford=carspeed(120,1.75)
Ferrari=carspeed(100,1.20)
BMW=carspeed(205,2.35)
Porsche=carspeed(155,1.85)
Audi=carspeed(190,2.10)
Jaguar=carspeed(255,2.45)
print("Ford speed in MPH:",Ford.cspeed())
print("Ferrari speed in MPH:",Ferrari.cspeed())
print("BMW speed in MPH:",BMW.cspeed())
print("Porsche speed in MPH:",Porsche.cspeed())
print("Audi speed in MPH:",Audi.cspeed())
print("Jaguar speed in MPH:",Jaguar.cspeed())
a=Ford.cspeed()
b=Ferrari.cspeed()
c=BMW.cspeed()
d=Porsche.cspeed()
e=Audi.cspeed()
f=Jaguar.cspeed()
def max_of_speed (a,b,c,d,e,f):
fastest=a
if fastest<b:
fastest=b
if fastest<c:
fastest=c
if fastest<d:
fastest=d
if fastest<e:
fastest=e
if fastest<f:
fastest=f
return fastest
print("The brand with the highest MPH is:",fastest)
#the(输出)
Ford speed in MPH: 68.0
Ferrari speed in MPH: 83.0
BMW speed in MPH: 87.0
Porsche speed in MPH: 83.0
Audi speed in MPH: 90.0
Jaguar speed in MPH: 104.0
The brand with the highest MPH is: 68.0
#期望的输出
Ford speed in MPH: 68.0
Ferrari speed in MPH: 83.0
BMW speed in MPH: 87.0
Porsche speed in MPH: 83.0
Audi speed in MPH: 90.0
Jaguar speed in MPH: 104.0
The brand with the highest MPH is: Jaguar
解决方法
不给变量起名字,而是向name
添加新属性carspeed
:
class carspeed:
def __init__ (self,name,distance,time):
self.name = name
self.distance=distance
self.time=time
def cars(self):
return (self.distance)//(self.time)
c1=carspeed('Ford',120,1.75)
c2=carspeed('Ferrari',100,1.20)
c3=carspeed('BMW',205,2.35)
cars = [c1,c2,c3]
fastestCar = max(cars,key=lambda item: item.cars()) # use Python's max function the get the fastest car!
print(fastestCar) # returns the instance!
print("The brand with the highest MPH is:",fastestCar.name)
出局:
<__main__.carspeed object at 0x1032e6c70>
The brand with the highest MPH is: BMW
,
您需要以某种方式保持与速度值相关联的品牌名称,以便以后打印。您已经有一个包含速度值的对象。为什么不向包含品牌名称的对象添加变量。然后,不要传递逻辑中的最终速度数字,而是传递每个品牌汽车的对象。
您可以在这里做更多的事情。代码的最大问题是,您不必将汽车的数量硬编码到代码中……也就是说,如果添加一辆汽车,所有代码都必须更改。您真正想要的是将您的汽车对象存储在列表或字典中,然后在该数据结构上进行迭代以进行处理,无论结构中有多少汽车,而无需关心有多少汽车。
这是您的代码的一个版本,可以解决所有这些问题,并为您提供所需的结果:
class car:
def __init__(self,time):
self.name = name
self.distance = distance
self.time = time
def cspeed(self):
return (self.distance) // (self.time)
cars = [
car("Ford",1.75),car("Ferrari",1.20),car("BMW",2.35),car("Porsche",155,1.85),car("Audi",190,2.10),car("Jaguar",255,2.45)
]
for car in cars:
print("%(name)s speed in MPH: %(speed)s" % {'name': car.name,'speed': car.cspeed()})
fastest = max(cars,key=lambda item: item.cspeed())
print("The brand with the highest MPH of %(speed)d is %(name)s"
% { 'speed': fastest.cspeed(),'name': fastest.name})
结果:
Ford speed in MPH: 68.0
Ferrari speed in MPH: 83.0
BMW speed in MPH: 87.0
Porsche speed in MPH: 83.0
Audi speed in MPH: 90.0
Jaguar speed in MPH: 104.0
The brand with the highest MPH of 104 is Jaguar
,
您本可以以更好的方式完成此操作,但无需更改很多代码即可执行此操作,但请注意,这不是最佳的执行方式
class carspeed:
def __init__ (self,time):
self.distance=distance
self.time=time
def cspeed(self):
return (self.distance)//(self.time)
Ford=carspeed(120,1.75)
Ferrari=carspeed(100,1.20)
BMW=carspeed(205,2.35)
Porsche=carspeed(155,1.85)
Audi=carspeed(190,2.10)
Jaguar=carspeed(255,2.45)
print("Ford speed in MPH:",Ford.cspeed())
print("Ferrari speed in MPH:",Ferrari.cspeed())
print("BMW speed in MPH:",BMW.cspeed())
print("Porsche speed in MPH:",Porsche.cspeed())
print("Audi speed in MPH:",Audi.cspeed())
print("Jaguar speed in MPH:",Jaguar.cspeed())
a=[Ford.cspeed(),'Ford']
b=[Ferrari.cspeed(),'Ferrari']
c=[BMW.cspeed(),'BMW']
d=[Porsche.cspeed(),'Porsche']
e=[Audi.cspeed(),'Audo']
f=[Jaguar.cspeed(),'Jaguar']
def max_of_speed (a,b,c,d,e,f):
fastest = a[0]
brand = a
if fastest<b[0]:
fastest=b[0]
brand = b
if fastest<c[0]:
fastest=c[0]
brand = c
if fastest<d[0]:
fastest=d[0]
brand = d
if fastest<e[0]:
fastest=e[0]
brand = e
if fastest<f[0]:
fastest=f[0]
brand = f
return brand[1]
print("The brand with the highest MPH is:",max_of_speed(a,f))
,
由于将所有车速放入一堆单独的变量中而不是某种集合中,因此您遇到了问题。我建议一本字典。这是您的代码的样子:
class Carspeed:
def __init__ (self,time):
self.distance=distance
self.time=time
def cspeed(self):
return (self.distance)//(self.time)
# for shorter version of this function - see below
def max_of_speed(car_speeds):
max_speed = None
brand = None
for name,value in car_speeds.items():
speed = value.cspeed()
if max_speed is None or speed > max_speed:
brand = name
max_speed = speed
return brand
car_speeds = {
'Ford': Carspeed(120,'Ferrari': Carspeed(100,'BMW': Carspeed(205,'Porsche': Carspeed(155,'Audi': Carspeed(190,'Jaguar': Carspeed(255,2.45),}
for name,value in car_speeds.items():
print(f"{name} speed in MPH:",value.cspeed())
print("The brand with the highest MPH is:",max_of_speed(car_speeds))
打印输出:
Ford speed in MPH: 68.0
Ferrari speed in MPH: 83.0
BMW speed in MPH: 87.0
Porsche speed in MPH: 83.0
Audi speed in MPH: 90.0
Jaguar speed in MPH: 104.0
The brand with the highest MPH is: Jaguar
我已尝试避免在上面的代码中使用任何过于复杂的内容,但这是max_of_speed
函数的单行版本,您可以根据需要使用它。
def max_of_speed(car_speeds):
return max(car_speeds,key=lambda name:car_speeds[name].cspeed())
,
只需按照您的代码和说明的方式进行,添加以下作业即可满足您的期望。
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。