如何将x.numpy的形状转换为矩阵n，m

如何解决如何将x.numpy的形状转换为矩阵n，m

我有以下数据集，

for x,y in dataset:    
    print(f'x= {x.numpy()},y = {y.numpy()}')

x= [0.1408765  0.09398889],y = 0.13090546429157257
x= [0.09398889 0.13090546],y = 0.1910403072834015
x= [0.13090546 0.1910403 ],y = 0.18664830923080444
x= [0.1910403  0.18664831],y = 0.14707279205322266
x= [0.18664831 0.14707279],y = 0.12366459518671036
x= [0.14707279 0.1236646 ],y = 0.29020464420318604
x= [0.1236646  0.29020464],y = 0.4495038092136383
x= [0.29020464 0.4495038 ],y = 0.599069356918335
x= [0.4495038  0.59906936],y = 0.5652390718460083
x= [0.59906936 0.5652391 ],y = 0.5409049987792969
x= [0.5652391 0.540905 ],y = 0.5281562805175781
x= [0.540905  0.5281563],y = 0.49817198514938354
x= [0.5281563 0.498172 ],y = 0.5296282172203064

当我打电话给x.shape时，我得到(2,)，但我想得到(len(x),2)的形状。我如何将x转换为所需的形状。同样，所需的y形状为(len(y),1)。

谢谢

解决方法

我想你的数据集看起来像

dataset = [[[0.1408765,0.09398889],0.13090546429157257],[[0.09398889,0.13090546],0.1910403072834015],[[0.13090546,0.1910403],0.18664830923080444],[[0.1910403,0.18664831],0.14707279205322266],[[0.18664831,0.14707279],0.12366459518671036],[[0.14707279,0.1236646],0.29020464420318604],[[0.1236646,0.29020464],0.4495038092136383],[[0.29020464,0.4495038],0.599069356918335],[[0.4495038,0.59906936],0.5652390718460083],[[0.59906936,0.5652391],0.5409049987792969],[[0.5652391,0.540905],0.5281562805175781],[[0.540905,0.5281563],0.49817198514938354],[[0.5281563,0.498172],0.5296282172203064]]

然后您将获得x，例如：

x = [row[0] for row in dataset]

和y：

y = [row[1] for row in dataset]

这是您的意思吗？

,

这个答案对我有用：

x = [row[0] for row in dataset]

y= [row[1] for row in dataset]

print(np.asarray(x).shape)

print(np.asarray(y).shape)