Oracle SQL，一张大表将列和百分比分布分类

如何解决Oracle SQL，一张大表将列和百分比分布分类

我有一个大的垫子视图，其中，我想对A列进行分类。对于A列，我需要B列的百分比分布。 列A是字符串值，列B是数字（长度）。此外，对于此列C的操作，我仅需要有效值（WHERE column_C ='active'），并且我需要D列的另一种类别，它代表B列中特定类型的值（WHERE column_D IN（“ kind_1”， kind_2“））。

到目前为止，我只对A列进行分类，对B列和百分比进行计数。

SELECT column_A,COUNT(*) AS column_A_count,(COUNT(*) / (SELECT COUNT(*) FROM schema.table_matview WHERE column_D IN ('kind_1','kind_2')) * 100 AS Percentage1
FROM schema.table_matview 
WHERE column_D IN ('kind_1','kind_2')
GROUP BY column_A;

应如何显示：

column_A_categorized  |column_B_percentage_to_column_A_kindA  |
_____________________ |_______________________________        |
category_A            |13.4%                                  |
_____________________ |_______________________________        |
category_B            |6.9%                                   |
_____________________ |_______________________________        |
category_C            |60.1%                                  |
_____________________ |_______________________________        |
category_D            |19,6%                                  |
_____________________ |_______________________________        |

与kind_B在第二列中相同，但它不适合它 ，因此第三列是column_B_percentage_to_column_A_kindB。

column A has values like: Paris,Lyon,Nancy,Marseilles,Bordeaux
column B : (length of streets)
441
107015762
3254
3255
102953236
162
116
1252
1252
3
1824
5513
736
136
3
136
3554
6
482
731
72
6531
3252


column C: active,not active

column D: streettype like road/way/street/motorway/footway

解决方法

根据您的评论，您需要简单的条件聚合：

SELECT column_A

   --  length of all streets passing the WHERE-condition,sum(column_B) AS all_street_length,sum(case when column_D = 'highway'  then column_B end) as highway_length,sum(case when column_D = 'motorway' then column_B end) as motorway_length,sum(case when column_D = 'highway'  then column_B end)
   / sum(column_B) * 100 AS highway_percentage,sum(case when column_D = 'motorway' then column_B end)
   / sum(column_B) * 100 AS motorway_percentage
FROM schema.table_matview 
WHERE column_C = 'active' -- street is still drivable
  -- AND column_D IN ('highway','motorway')
GROUP BY column_A;

这将返回基于 all 条街道的百分比，而不仅仅是高速公路/高速公路（highway_percentage + motorway_percentage小于100％）。如果您取消注释AND column_D IN ('highway','motorway')，则仅基于这些街道（highway_percentage + motorway_percentage总计为100％）