按下鼠标两次后退出的汇编程序

如何解决按下鼠标两次后退出的汇编程序

所以现在我只能让它循环并等待点击，但是，一旦我点击，程序认为我仍然在按住点击或其他东西，因为一旦我点击按钮状态就永远不会改变.所以程序只是循环到无穷大。

这是我所拥有的：

.286
TITLE ''
.MODEL SMALL

.STACK

.DATA
    clickR DB 'Right click',10,13,'$'
    ; clickI DB 'Left click','$'

.CODE



main PROC FAR
    MOV AX,@DATA
    MOV DS,AX

    MOV AX,0h       ; Init mouse
    INT 33h

    MOV AX,01h      ; Show pointer
    INT 33h

mouse:
    MOV AX,05h      ; Query Button-Pressed Counter
    MOV BX,00h      ; Left button
    INT 33h

    CMP AX,01h      ; Check left button status
    JNE mouse        ; Not pressed? Go back
    CMP BX,02h      ; Check if it has been pressed twice
    JB right         ; < 2? Go to label
    JAE quit         ; >= 2? quit

    JMP mouse

right:
    MOV AH,09h       ; Print that r-click has been pressed
    LEA DX,clickR
    INT 21h
    JMP mouse         ; Go back to mouse loop

quit:
    MOV AX,4C00h
    INT 21h
main ENDP

END main

解决方法

使用 AH=3 RETURN POSITION AND BUTTON STATUS 而不是 AH=5。

当它返回BX=1（左按钮按下）时，重复查询并等待BX=0（按钮向上）。

如果您需要检测双击，请再次重复这两个查询。

,

基于 vitsoft 所说的解决方案

现在，这是我修复它的方式（它可能不是最佳的，但它有效）：

.286
TITLE ''
.MODEL SMALL

.STACK

.DATA
    clickR DB 'Right click',10,13,'$'
    released DB 'Released','$'

.CODE

rightC PROC NEAR
    MOV AH,09h
    LEA DX,clickR
    INT 21h
    RET
rightC ENDP

releaseStr PROC NEAR
    MOV AH,released
    INT 21h
    RET
releaseStr ENDP


main PROC FAR
    MOV AX,@DATA
    MOV DS,AX

    MOV AX,0h       ; Init mouse
    INT 33h

    MOV AX,01h      ; Show pointer
    INT 33h

    XOR CX,CX       ; Init counter
    PUSH CX          ; Save counter

mouse:
    MOV AX,03h      ;  Query Position / Button Status
    INT 33h

    CMP BX,01h      ; Check left button status
    JNE mouse        ; Not pressed? Go back
    CALL rightC      ; Print that r-click has been pressed

release:
    MOV AX,03h      ; Query Position / Button Status
    INT 33h

    CMP BX,00h      ; Check button status (None)
    JNE release      ; Still no released? Go back
    CALL releaseStr  ; Print that r-click has been released

    POP CX           ; Return counter
    INC CX           ; Counter + 1 = r-click has been pressed and released one time
    CMP CX,02h      ; Check if this has happened twice
    JAE quit         ; Yes? quit
    PUSH CX          ; No? Save counter

    JMP mouse        ; Go back to mouse loop

quit:
    MOV AX,4C00h
    INT 21h
main ENDP

END main

,

CMP AX,01h      ; Check left button status
JNE mouse        ; Not pressed? Go back

如果您想等待 2 次点击，您还必须允许释放按钮！上面的代码使这变得不可能，因为您坚持让按钮处于按下状态。

接下来的代码等待鼠标左键点击 2 次并退出：

    MOV AX,0000h    ; Init mouse
    INT 33h
    MOV AX,0001h    ; Show pointer
    INT 33h
mouse:
    MOV AX,0005h    ; Query Button-Pressed Counter
    XOR BX,BX       ; Left button
    INT 33h
    CMP BX,2        ; Check if it has been pressed twice
    JB  mouse         ; < 2? Go to label
quit:
    MOV AX,4C00h
    INT 21h