如何解决迅捷可编码字典
我在编码方面遇到了问题。任何帮助将不胜感激。我的操场上有以下物品
我的JSON文件中的样本。它具有更多元素,将其缩小为较小的子集。
{
"Metadata" : {
"generated" : {
"timestamp" : 1549331723,"date" : "2019-02-04 20:55:23"
}
},"data" : {
"CA" : {
"country-id" : 25000,"country-iso" : "CA","country-eng" : "Canada","country-fra" : "Canada","date-published" : {
"timestamp" : 1544561785,"date" : "2018-12-11 15:56:25","asp" : "2018-12-11T15:56:25.4141468-05:00"
}
},"BM" : {
"country-id" : 31000,"country-iso" : "BM","country-eng" : "Bermuda","country-fra" : "Bermudes","date-published" : {
"timestamp" : 1547226095,"date" : "2019-01-11 12:01:35","asp" : "2019-01-11T12:01:35.4748399-05:00"
}
}
}
}
来自quicktype应用程序。它为Datum生成了一个字典。 json的结构方式,国家/地区缩写没有标签。
import Foundation
// MARK: - Welcome
struct Welcome: Codable {
let Metadata: Metadata?
let data: [String: Datum]?
}
// MARK: - Datum
struct Datum: Codable {
let countryID: Int?
let countryISO,countryEng,countryFra: String?
let datePublished: DatePublished?
enum CodingKeys: String,CodingKey {
case countryID = "country-id"
case countryISO = "country-iso"
case countryEng = "country-eng"
case countryFra = "country-fra"
case datePublished = "date-published"
}
}
// MARK: - DatePublished
struct DatePublished: Codable {
var timestamp: Int
var date,asp: String
}
// MARK: - Metadata
struct Metadata: Codable {
var generated: Generated
}
// MARK: - Generated
struct Generated: Codable {
var timestamp: Int
var date: String
}
// MARK: - Encode/decode helpers
class JSONNull: Codable,Hashable {
public static func == (lhs: JSONNull,rhs: JSONNull) -> Bool {
return true
}
public var hashValue: Int {
return 0
}
public func hash(into hasher: inout Hasher) {
// No-op
}
public init() {}
public required init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
if !container.decodeNil() {
throw DecodingError.typeMismatch(JSONNull.self,DecodingError.Context(codingPath: decoder.codingPath,debugDescription: "Wrong type for JSONNull"))
}
}
public func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
try container.encodeNil()
}
}
从我的代码中,我可以加载json文件,我不确定如何使用字典在这里处理数据,并且国家/地区没有国家/地区缩写的名称。
guard let url = Bundle.main.url(forResource: "data",withExtension: "json") else { return 0 }
let jsonData = try Data(contentsOf: url)
注意:这是我之前的问题的后续解答:Swift Codable Parsing keyNotFound
解决方法
您的数据模型已经正确定义(但是,我建议您进行一些名称更改并从属性中删除可变性/可选性)。
一旦解析了JSON,就不必保留Dictionary
,因为键实际上是country-iso
键下值的一部分。
因此,一旦您解码了Root
对象,我建议您简单保留root.data.values
,这将为您提供Array<CountryData>
,此后您可以轻松处理。
struct Root: Codable {
let data: [String: CountryData]
}
struct CountryData: Codable {
let countryID: Int
let countryISO,countryEng,countryFra: String
let datePublished: DatePublished
enum CodingKeys: String,CodingKey {
case countryID = "country-id"
case countryISO = "country-iso"
case countryEng = "country-eng"
case countryFra = "country-fra"
case datePublished = "date-published"
}
}
// MARK: - DatePublished
struct DatePublished: Codable {
let timestamp: Int
let date,asp: String
}
do {
let root = try JSONDecoder().decode(Root.self,from: countryJson.data(using: .utf8)!)
let countries = root.data.values
print(countries)
} catch {
error
}
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。