我如何随机调用函数C＃ 其他注意事项：

如何解决我如何随机调用函数C＃ 其他注意事项：

我正在制作一款无尽的汽车驾驶游戏，我想在玩家的汽车靠近敌方汽车之一时随机调用switchLane函数之一。关键是要在接近时使其他一些汽车切换到随机车道。我主要要寻找的是一种在每次接近时随机调用这4个switchLane函数之一的方法。

public class EnemyScript : MonoBehavIoUr
{
 public float speed;
 private GameObject playerTransform;
 private GameObject enemyCarPrefab;
 private float distancetoNextCar;
 public float distance;

 private float roadWidth;
 private float lane1 = 7.25f;
 private float lane2 = 2.45f;
 private float lane3 = 2.4f;
 private float lane4 = 7.3f;

 // Start is called before the first frame update
 void Start()
 {
    
 }

 // Update is called once per frame
 void Update()
 {
     playerTransform = GameObject.FindGameObjectWithTag("Player");
     enemyCarPrefab = GameObject.FindGameObjectWithTag("BaseCar");

     distancetoNextCar = enemyCarPrefab.transform.position.z - distance;
     if (playerTransform.transform.position.z > distancetoNextCar)
     {
         switchLane1();
         switchLane2();
         switchLane3();
         switchLane4();
     }
 }


 private void switchLane1()
 {
     Vector3 targetPos1 = new Vector3(-lane1,0);
     transform.position += (targetPos1 * speed * Time.deltaTime);



     if (transform.position.x <= -lane1)
     {
         Vector3 newPositionLeft = new Vector3(-lane1,transform.position.y,transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane1)
     {
         Vector3 newPositionRight = new Vector3(lane1,transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane2()
 {
     Vector3 targetPos2 = new Vector3(-lane2,0);
     transform.position += (targetPos2 * speed * Time.deltaTime);



     if (transform.position.x <= -lane2)
     {
         Vector3 newPositionLeft = new Vector3(-lane2,transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane2)
     {
         Vector3 newPositionRight = new Vector3(lane2,transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane3()
 {
     Vector3 targetPos3 = new Vector3(lane3,0);
     transform.position += (targetPos3 * speed * Time.deltaTime);



     if (transform.position.x <= -lane3)
     {
         Vector3 newPositionLeft = new Vector3(-lane3,transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane3)
     {
         Vector3 newPositionRight = new Vector3(lane3,transform.position.z);
         transform.position = newPositionRight;
     }

 }

 private void switchLane4()
 {
     Vector3 targetPos4 = new Vector3(lane4,0);
     transform.position += (targetPos4 * speed * Time.deltaTime);



     if (transform.position.x <= -lane4)
     {
         Vector3 newPositionLeft = new Vector3(-lane4,transform.position.z);
         transform.position = newPositionLeft;
     }
     if (transform.position.x >= lane4)
     {
         Vector3 newPositionRight = new Vector3(lane4,transform.position.z);
         transform.position = newPositionRight;
     }

 }
}

解决方法

例如

// for more flexibility rather use an array
// You should also add the ability to change it via the Inspector
[SerializeField]
private float[] lanes = new []
{
    7.25f,2.45f,2.4f,7.3f
};

// pass the index of the lane to your method
// this way you can handle all lanes with a single method
private void SwitchToLane(int index)
{
    Debug.Log($"Switching to lane {index}",this);

    // Get the float at given index in lanes
    var x = lanes[index];

    var targetPos = new Vector3(x,0);
    transform.position += (targetPos * speed * Time.deltaTime);

    if (transform.position.x <= -x)
    {
       var newPositionLeft = new Vector3(-x,transform.position.y,transform.position.z);
       transform.position = newPositionLeft;
    }
    // Rather use 'else if' when it is already clear that only one case can be true at the same time
    else if (transform.position.x >= x)
    {
       var newPositionRight = new Vector3(x,transform.position.z);
       transform.position = newPositionRight;
    }
}

然后致电

// Call this to switch to any random lane
private void SwitchToRandomLane()
{
    // generate a random int between 0 and lanes.Length - 1
    // second parameter is EXCLUSIVE!
    var random = Random.Range(0,lanes.Length); 

    SwitchToLane(random);
}
        

---

其他注意事项：

1. 您还需要以某种方式更改Update中的条件检查。目前，只要玩家一次到达距离阈值以下，就可以切换车道每帧！

2. 您可能希望在某个地方存储当前通道索引，因此在调用SwitchToRandomLane时，当前索引将从选项中排除，您只能确定切换到与您已经使用的通道不同的通道上。

这两点我都留给你。

,

您可以创建一个随机数

int randomNum = Random.Range(0,4);

并在具有四个功能的switch上使用它，诸如此类

switch(randomNum){
case 0:
  switchLane1();
break;
case 1:
  switchLane2();
break;
case 2:
  switchLane3();
break;
case 3:
  switchLane4();
break;
}

但是我敢肯定有一个更好的解决方案，我看到了很多重复的代码，也许您可​​以针对这四种情况用一个参数来做一个函数，而只需发送一个带有方向或数字的参数即可。