通过调用模型函数将烧瓶宁静字段编组为列表

如何解决通过调用模型函数将烧瓶宁静字段编组为列表

我有一个Location模型和一个Weather模型。每个Location对象都有多个Weather对象（一对多关系）。

class Weather(db.Model):
    id = db.Column(db.Integer,primary_key=True)
    date = db.Column(db.DateTime,nullable=False)
    _temperature = db.Column(db.String(500),nullable=False)
    lat = db.Column(db.Float,nullable=False)
    lon = db.Column(db.Float,nullable=False)
    location = db.relationship('Location',backref=db.backref('weathers',lazy=True))
    __table_args__= (
        db.ForeignKeyConstraint(['lat','lon'],['location.lat','location.lon']),)
    def add_temperature(self,temperature):
        if not self._temperature:
            self._temperature = temperature
        else:
            self._temperature = self._temperature + ';' + temperature
    
    def get_temperature(self):
        return self._temperature.split(';')

_temperature对象中的Weather字段存储多个以；作为字符串： 37.7;37.1;36.7;36.3;36.0;35.6;35.2;35.1;35.9;38.1;40.3;42.4;43.8;44.9;45.6;45.7;44.9;43.0;41.7;40.7;39.8;39.1;38.4;37.9 我想整理位置对象，以便对特定位置的GET调用的响应返回Weather对象的数组：

[
    {
        "id": 1,"date": "1985-01-01","location": {
            "lat": 36.1189,"lon": -86.6892,"city": "Nashville","state": "Tennessee"
        },"temperature": [
            37.3,36.8,36.4,...
        ]
    },...
]

我尝试像这样定义marshal_with字段：

resource_fields = {
    'id': fields.Integer,'date': fields.DateTime('iso8601'),'temperature': fields.List(fields.nested(fields.Float,attribute='get_temperature')),'location': fields.nested(location_details)
}

但是我得到了"temperature":null的回复。有什么方法可以在编组字段中调用Weather.get_temperature函数？我的资源定义为：

class WeatherList(Resource):
    @marshal_with(resource_fields)
    def get(self):
        args = WeatherGetParser().parse_args()
        result = Weather.query.filter_by(lat=args['lat'],lon=args['lon']).all()
        return result