用标准实施代替boost

如何解决用标准实施代替boost

什么是替代此方法的正确方法？

std::ostringstream buf;
std::for_each(bd.begin(),bd.end(),buf << boost::lambda::constant("&nbsp;") << boost::lambda::_1);

使用不使用boost的实现吗？这是我尝试过的：

std::string backspace("&nbps;");
std::ostringstream buf;        
std::for_each(bd.begin(),buf << backspace << std::placeholders::_1);

第二个'

error C2679: binary '<<' : no operator found which takes a right-hand operand of type 'std::_Ph<1>' (or there is no acceptable conversion)

解决方法

import tkinter import threading import time global msg def gui(): root = tkinter.Tk() box = tkinter.Text(width=90,height=30,font=("Lucida Console",10)) box.pack(pady=20) box.insert(tkinter.END,msg) #this updated msg should be shown box.configure(state=tkinter.DISABLED) root.mainloop() def loop(): global msg for x in range(100): msg = str(x) time.sleep(1) if __name__ == '__main__': p1 = threading.Thread(target=gui) p2 = threading.Thread(target=loop) p1.start() p2.start() 是一种奇妙的怪兽，它会将lambda反向移植到C ++ 03。与您的代码等效的是：

boost::lambda

...甚至：

std::ostringstream buf;
std::for_each(bd.begin(),bd.end(),[&](auto const &v) { buf << "&nbsp;" << v; });