如何汇总默认dict数据

如何解决如何汇总默认dict数据

我有一个字典列表，如下所示：

result = {
    "resultset": [
        {"name": "DOG","threshold": Decimal("1.45600000"),"current_value": 124},{"name": "DOG","current_value": 14},"current_value": 1},{"name": "CAT","current_value": 24},"current_value": 4},]
}

现在我想实际做2件事，基本上是在我得到的地方做一个凝结：

1. 当前值列表[]
2. 阈值的平均值

所以最后我想看看：

{
'DOG': {'current_values': [124,14,1],'threshold': the average of threshold},'CAT': {'current_values': [24,4],'threshold': the average of threshold}
}

我可以使用其中的一半来获取current_values列表，但不能使用默认的dict来获取整个列表，

all_animals  = defaultdict(list)
     for i in result['resultset']:                
           all_animals[i['name']].append(float(i['current_value']))

有人可以帮我吗

解决方法

带有defaultdict和statistics的蛋糕：

from decimal import Decimal
from collections import defaultdict
import statistics

result = {
    "resultset": [
        {
            "name": "DOG","threshold": Decimal("1.45600000"),"current_value": 124,},{
            "name": "DOG","current_value": 14,"current_value": 1,{
            "name": "CAT","current_value": 24,"current_value": 4,]
}

current_values_by_name = defaultdict(list)
thresholds_by_name = defaultdict(list)
for x in result["resultset"]:
    current_values_by_name[x["name"]].append(x["current_value"])
    thresholds_by_name[x["name"]].append(x["threshold"])

aggregate_result = {
    name: {
        "current_values": current_values_by_name[name],"threshold": statistics.mean(thresholds_by_name[name]),}
    for name in current_values_by_name
}

print(aggregate_result)

输出

{
    "DOG": {
        "current_values": [124,14,1],"threshold": Decimal("1.456"),"CAT": {
        "current_values": [24,4],}