如何解决是否有更简洁的方法来返回指定文本中包含字符组合的单词
我需要创建一个函数,该函数接受文本块作为参数,然后匹配并返回包含至少一个以下字符串/字符组合的单词:
- tion (as in navigation,isolation,or mitigation)
- ex (as in explanation,exfiltrate,or expert)
- ph (as in philosophy,philanthropy,or ephemera)
- ost,ist,ast (as in hostel,distribute,past)
我已经使用了for循环来搜索这些模式并将其附加到列表中:
def f(string):
string_list = string.split()
match_list = []
for word in string_list:
if "tion" in word:
match_list.append(word)
if "ex" in word:
match_list.append(word)
if "pht" in word:
match_list.append(word)
if "ost" in word:
match_list.append(word)
if "ist" in word:
match_list.append(word)
if "ast" in word:
match_list.append(word)
return match_list
print (f(text))
我如何才能更有效地编写此代码?
解决方法
您可以在def f(string):
string_list = string.split()
match_list = []
part_list = ["tion","ex","pht","ost","ist","ast"]
for word in string_list:
for part in part_list:
if part in word:
match_list.append(word)
return match_list
上添加另一个循环:
fetch().then().catch(err => ...)
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