微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

在python中从MySql数据库获取数据时出错

如何解决在python中从MySql数据库获取数据时出错

我正在尝试使用Python中的WHERE子句从MysqL数据库获取密码,并将密码存储在变量“ DbPassword”中,但是当我打印“ DbPassword”时,它将打印“ None” 谁能解释为什么会这样,我该如何解决? 谢谢I have attached a ScreenShot of my IDE where the entire function and Output can be seen

def searchdb(self):        
    User = (self.Username.get())
    pas = (self.Password.get())
   
    myconn = MysqL.connector.connect(host = "localhost",user = "root",passwd = "qwerty321",database = "admin")
    
    if len(User) == 0 and len(pas) == 0 :
       tkinter.messageBox.showinfo("Pharmacy Management System","Please fill in the Login Details")
    elif len(User) == 0 and len(pas) != 0 :
        tkinter.messageBox.showinfo("Pharmacy Management System","Please Enter a Username")
    elif len(User) != 0 and len(pas) == 0:
         tkinter.messageBox.showinfo("Pharmacy Management System","Please enter a Password")
    else:
        try:
            #seacrch data
            #print("%s\n%s"%(User,pas) )
            
            sql = "SELECT password FROM users WHERE user_name = '%s'"
            cur = myconn.cursor()
            cur.execute(sql,(User))
           
            DbPassword = cur.fetchone()
            
            print("%s"%(DbPassword))
            
            if (pas == str(DbPassword)) :
                self.btnRegistration.config(state=norMAL)
                self.btnHospital.config(state=norMAL)
            else:
                tkinter.messageBox.askokcancel("Pharmacy Management System","You have entered an invalid login details")
                self.btnRegistration.config(state=disABLED)
                self.btnHospital.config(state=disABLED)
                self.Username.set("")
                self.Password.set("")
                self.txtUsername.focus()
        except Error as e:
               # tkinter.messageBox.showinfo("Pharmacy Management System","NO RECORD FOUND !")
                myconn.rollback()
                Window1.Reset(self)
    myconn.close()

解决方法

最后获得答案进行了一些更改 修改: $products = []; for ($i = 0; $i < count($data['products']); $i++) { $recipes[$data['products'][$i]['id']] = $data['products'][$i]; unset($products[$data['products'][$i]['id']]['id']); } $budget->products()->sync($products); $budget->products = $data['products']; 到: sql = "SELECT password FROM users WHERE user_name = '%s'" cur.execute(sql,(User)) 并按预期工作。

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。