如何解决如何从子表中选择一个随机ID?
我正在使用10.4.13-MariaDB。我有一个父表和一个子表。
父表(任务)
id parent_id
4 # <- Main (parent theme) Level 2
5 4 <- child `discovered check` (level 2)
6 4 <- child `windmill` (level 2)
7 # <- Main (parent theme) Level 3
8 7 <- child `discovered check - level 3` (level 3)
9 7 <- child `windmill - level 3` (level 3)
10 # <- Main (parent theme) Level 1
11 10 <- child `discovered check - winning a piece` (level 1)
12 10 <- child `discovered check - mate in one` (level 1)
界面看起来像
id task_id
52 5 <- belongs to `discovered check` (level 2)
61 6 <- belongs to `windmill` (level 2)
25 6 <- belongs to `windmill` (level 2)
70 11 <- belongs to `discovered check - winning a piece` (level 1)
53 12 <- belongs to `discovered check - mate in 1` (level 1)
62 9 <- belongs to `windmill - level 3` (level 3)
27 9 <- belongs to `windmill - level 3` - (level 3)
72 8 <- belongs to `discovered check - level 3` - (level 3)
预期结果:
task_id id
5 52 <- random puzzle from level 2
11 70 <- random puzzle from level 1
8 72 <- random puzzle from level 3
我的小提琴:https://dbfiddle.uk/?rdbms=mariadb_10.4&fiddle=7bed2a19a0f98abccbe06ba9e0ae358b
解决方法
WITH cte AS ( SELECT tasks.id task_id,puzzles.puzzle_id,row_number() over (partition by tasks.id order by rand()) rn
FROM tasks
JOIN puzzles ON tasks.id = puzzles.task_id )
SELECT task_id,puzzle_id
FROM cte
WHERE rn = 1;
需要8.0+版本或MariaDB 10.2 +
select tasks.id task_id,rand_puzzle.puzzle_id
from tasks,lateral ( select puzzle_id
from puzzles
where tasks.id = puzzles.task_id
order by rand() limit 1 ) rand_puzzle;
需要版本8.0.14 +。
如果您需要某些子树的数据,请仅从以前的递归CTE中的tasks
表中提取该子树。
每个主要任务需要一个难题。因此,首先(使用递归查询)从层次上查找属于主任务的所有任务,然后加入谜题并为每个主任务选择一个。
(主要任务是您在请求中称为“级别”。)
with recursive cte (main_task_id,task_id) as
(
select parent_id,task_id
from tasks
where parent_id in (select id from tasks where parent_id is null)
union all
select cte.main_task_id,t.task_id
from cte
join tasks t on t.parent_id = cte.task_id
),randomly_numbered as
(
select
cte.main_task_id,p.task_id,p.id as puzzle_id,row_number() over (partition by main_task_id order by rand()) as rn
from cte
join puzzle p on p.task_id = cte.task_id
)
select
-- main_task_id,task_id,puzzle_id
from randomly_numbered
where rn = 1
order by main_task_id;
,
具有ROW_NUMBER()
窗口功能:
with cte as (
select p.*,row_number() over (partition by t.parent_id order by rand()) rn
from puzzles p inner join tasks t
on t.id = p.task_id
)
select task_id,id
from cte
where rn = 1
请参见demo。
row_number()
的分区应按parent_id
的列tasks
进行划分,因此每个主题的结果都有1行。
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