如何计算嵌套元组列表中字符串的出现次数？

如何解决如何计算嵌套元组列表中字符串的出现次数？

我在python中有一个嵌套的元组列表：

myList = [(12345,"John Doe"),(345678,'Marie Doe'),(434566,(665533,(23456,'John Doe'),(657332211,'Amanda Doe')]

并尝试将名称出现为两个单独的列表：

occurrences = [2,3,1]
names = ['John Doe','Marie Doe','Amanda Doe']

到目前为止，这给了我嵌套嵌套元组中的所有项目，但不确定如何产生以上内容：

Total = len(myList)

有人可以帮我吗？预先谢谢你！

解决方法

您可以做的是创建一个dict，其中键是名称，值是它们在myList中的计数。

 myList = [(12345,"John Doe"),(345678,'Marie Doe'),(434566,(665533,(23456,'John Doe'),(657332211,'Amanda Doe')]

# Initializing a dict with key: name and value: 0.
dict_name_count = {name: 0 for _,name in myList}

# Iterating over tuples in `myList`,picking name (the second entry in tuple) ignoring the number.
for _,name in myList:
    dict_name_count[name] += 1

print(dict_name_count)
# Results in: {'John Doe': 2,'Marie Doe': 3,'Amanda Doe': 1}

# To get separate lists:
names = list(dict_name_count.keys())
occurrences = list(dict_name_count.values())

,

这是我要用熊猫做的事情：

import pandas as pd

df = pd.DataFrame(myList).groupby(1,as_index=False).count()

occurrences = df[0].to_list()
names = df[1].to_list()

输出：

names : ['Amanda Doe','Joe Doe','John Doe','Marie Doe']
occurrences : [1,1,3]

,

您可以将名称解压缩到一个列表中，然后只运行该列表的计数：

all_names = [elem[1] for elem in myList]
names = []
occurrencs = []
for name in set(all_names):
    names.append(name)
    occurrences.append(all_names.count(name))

,

尝试

    myList = [(12345,'Amanda Doe')
          ]
namelist=[name[1] for name in myList]
names=[]
for name in namelist:
    if name not in names:
        names.append(name)

occurrences=[namelist.count(name) for name in names]
print(occurrences)
print(names)