如何解决如何在C#中使一侧圆形按钮?
我找到了代码:
GraphicsPath GetRoundpath(RectangleF Rect,int radius,float width=0)
{
//Fix radius to rect size
radius = (int) Math.Max(( Math.Min(radius,Math.Min(Rect.Width,Rect.Height)) - width),1);
float r2 = radius / 2f;
float w2 = width / 2f;
GraphicsPath GraPHPath = new GraphicsPath();
//Top-Left Arc
GraPHPath.AddArc(Rect.X + w2,Rect.Y + w2,radius,180,90);
//Top-Right Arc
GraPHPath.AddArc(Rect.X + Rect.Width - radius - w2,270,90);
//Bottom-Right Arc
GraPHPath.AddArc(Rect.X + Rect.Width - w2 - radius,Rect.Y + Rect.Height - w2 - radius,90);
//Bottom-Left Arc
GraPHPath.AddArc(Rect.X + w2,Rect.Y - w2 + Rect.Height - radius,90,90);
//Close line ( Left)
GraPHPath.AddLine(Rect.X + w2,Rect.Y + Rect.Height - r2 - w2,Rect.X + w2,Rect.Y + r2 + w2);
//GraPHPath.Closefigure();
return GraPHPath;
}
有人可以解释一下我应该如何更改按钮,使按钮只有一侧圆角吗?
解决方法
经过研究,我设法为将来的用户制作了它。 这是仅将右下角四舍五入的代码:
radius = (int)Math.Max((Math.Min(radius,Math.Min(Rect.Width,Rect.Height)) - width),1);
float r2 = radius / 2f;
float w2 = width / 2f;
GraphicsPath GraphPath = new GraphicsPath();
GraphPath.AddLine(Rect.X + w2,Rect.Y + w2,Rect.X,Rect.Y);
GraphPath.AddLine(Rect.X + Rect.Width,Rect.Y,Rect.X + Rect.Width - w2,Rect.Y);
GraphPath.AddArc(Rect.X + Rect.Width - w2 - radius,Rect.Y + Rect.Height - w2 - radius,radius,90);
GraphPath.AddLine(Rect.X + w2,Rect.Y - w2 + Rect.Height,Rect.X - w2,radius);
GraphPath.AddLine(Rect.X + w2,Rect.Y + Rect.Height + r2 + w2 + Rect.Y,Rect.X + w2,Rect.Y + Rect.Y);
return GraphPath;
左上方
GraphPath.AddLine(Rect.X + w2,Rect.Y);
GraphPath.AddArc(Rect.X + Rect.Width - radius - w2,270,90);
GraphPath.AddLine(Rect.X + Rect.Width-w2,Rect.Y + Rect.Height,Rect.X+Rect.Width,Rect.Y+Rect.Height-w2);
GraphPath.AddLine(Rect.X + w2,radius);
GraphPath.AddLine(Rect.X + w2,Rect.Y + Rect.Y);
return GraphPath;
右上方
GraphPath.AddArc(Rect.X + w2,180,90);
GraphPath.AddLine(Rect.X + Rect.Width,Rect.Y);
GraphPath.AddLine(Rect.X + Rect.Width - w2,Rect.X + Rect.Width,Rect.Y + Rect.Height - w2);
GraphPath.AddLine(Rect.X + w2,Rect.Y + Rect.Height - r2 - w2,Rect.Y + r2 + w2);
return GraphPath;
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