如何解决是否可以在另一个回调中调用useCallback
在组件A中:
const getonClick = useCallback(
(rec: GenericRec): (() => void) => () => {
setSelectedRecord(rec);
},[],);
在A的子B子中:
const openRecord = useCallback(
(row: Row<Record>) => () => {
getonClick({ id: row.original.id,name: row.original.name });
},[getonClick],);
解决方法
在两个useCallback
调用中,您都有一个额外的功能层。与useMemo
不同,useCallback
直接接受应记住的回调,而不是接受构建回调的函数。
所以:
const getOnClick = useCallback(
(rec: GenericRec): (() => void) => {
// ^−−−− no () => here
console.log("getOnClick");
setSelectedRecord(rec);
},[],);
const openRecord = useCallback(
(row: Row<Record>) =>
// ^−−−− no () => here
getOnClick({ id: row.original.id,name: row.original.name }),[getOnClick],);
实时示例(带有TypeScript类型注释的注释):
const { useState,useCallback } = React;
function Example() {
const [selectedRecord,setSelectedRecord] = useState(null);
const getOnClick = useCallback(
(rec/*: GenericRec*/)/*: (() => void)*/ => {
console.log("getOnClick");
setSelectedRecord(rec);
},[]/*,*/
);
const openRecord = useCallback(
(row/*: Row<Record>*/) =>
// ^−−−− no () => here
getOnClick({ id: row.original.id,[getOnClick]/*,*/
);
const addRecord =() => {
console.log("addRecord");
openRecord({
original: {
id: 1,name: "The record"
}
});
};
return (
<div>
<input type="button" value="Click Me" onClick={addRecord} disabled={!!selectedRecord} />
{selectedRecord && <span>Selected record: "{selectedRecord.name}" ({selectedRecord.id})</span>}
{!selectedRecord && <em>No record selected</em>}
</div>
);
}
ReactDOM.render(<Example/>,document.getElementById("root"));
<div id="root"></div>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.13.0/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.13.0/umd/react-dom.production.min.js"></script>
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