如何在JavaScript中获取全名和年龄？

如何解决如何在JavaScript中获取全名和年龄？

您好，我目前仅在学习javascript，我有一个问题！

问题

76498.0_20150501

这就是我写的

selected_B_C

规则。

• 如果人的名字（全名）和全名都必须合并

我想获得这样的价值 let result = [[“ Joe”，42] [“ Mary Jenkins”，36]，[“ Kim”，40]]

解决方法

我认为您的数据结构不正确。我假设您有一个类似这样的对象数组。

let arr = [
  {
    'firstName': 'Joe','age': 42,'gender': 'male',},{
    'firstName': 'Mary','lastName': 'Jenkins','age': 36,'gender': 'female',{
    'firstName': 'Kim','age': 40,}
];

然后您的测试功能将如下所示-

function test5(arr) {
 let result=[];
 arr.forEach(function(elm){
  let entry={
    'name':elm['firstName'],'age':elm['age']
  };

  // this if will put append last name if present in elm
  if(elm['lastName']){
    entry['name']=entry['name']+' '+elm['lastName'];
  }
  result.push(entry)
 })
 return result;
}

您将获得此结果-

[
    {name:"Joe",age:42},{name:"Mary Jenkins",age:36},{name:"Kim",age:40},]

,

您可以尝试将嵌套数组转换为对象数组并进行对象迭代

let arr = [
  [
    ["firstName","Joe"],["age",42],["gender","male"]
  ],[
    ["firstName","Mary"],["lastName","Jenkins"],36],"female"]
  ],[
    ["lastName","Kim"],40],"female"]
  ]
];


const createObject = a => {
  const res = {};
  for (let el of a) {
    res[el[0]] = el[1];
  }
  return res;
};

const results = [];
arr.forEach(a => {
  if (a && a.length !== 0) {
    const destructedArray = createObject(a);

    destructedArray["name"] = "";
    if (destructedArray.firstName && destructedArray.lastName) {
      destructedArray.name = `${destructedArray.firstName},${destructedArray.lastName}`;
    } else if (destructedArray.lastName) {
      destructedArray.name = `${destructedArray.lastName}`;
    } else {
      destructedArray.name = `${destructedArray.firstName}`;
    }
    results.push([destructedArray.name,destructedArray.age]);
  }
});

console.log(results);