如何解决在列表理解的else块中分配值
occupied = [8,9,10]
broken = [1,2,3]
output = ['occupied' if x in occupied else x in broken for x in range(1,11)]
desired_output = ['broken','broken',False,'occupied','occupied']
能否一口气实现以上目标？
当前我正在进行两次迭代
['broken' if x2==True else x2 for x2 in ['occupied' if x in occupied else x in broken for x in range(1,11)] ]
我正在寻找这样的东西
['occupied' if x in occupied else 'broken' if x in broken for x in range(1,11)]
但这是不正确的语法
解决方法
您几乎已经拥有了，只需在解决方案中添加一个else子句（第二个if表达式）：
output = ["broken" if x in broken else 'occupied' if x in occupied else False for x in range(1,11)]
# Out[5]: ['broken','broken',False,'occupied','occupied']
如果我理解正确，这应该对您有用
occupied = [8,9,10]
broken = [1,2,3]
["occupied" if x in occupied else "broken" if x in broken else False for x in range(1,11)]
输出：
['broken','occupied']
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