如何解决在函数内部时,Python tkinter代码无法运行
def display_rain():
rain_image = Image.open("./images/rain_jpeg.jpg")
rain_resized = rain_image.resize((250,250),Image.ANTIALIAS)
rain_tk = ImageTk.PhotoImage(rain_resized)
rain_label = tk.Label(root,image = rain_tk)
rain_label.grid(row = 0,column = 0)
rain_label.pack()
display_rain()
该代码在函数外部运行良好,但在函数内部似乎根本没有运行。我尝试重新启动Python并重命名该功能。
解决方法
您的图像正在被垃圾收集。这行得通。
import tkinter as tk
from PIL import Image,ImageTk
root = tk.Tk()
root.geometry("800x600")
#store all images in this dict so garbage collection will leave them alone
#it doesn't have to be named "images"; it just has to be a dict
images = dict()
def display_rain(row=0,column=0):
#create and store the image if it doesn't exist
if 'rain_tk' not in images:
#unless you are making mips of this image you should probably
#~make it the proper size and get rid of the resize part
image = Image.open("./images/rain_jpeg.jpg").resize((250,250),Image.ANTIALIAS)
#you can add a name to reference the image by
#this makes it cleaner than accessing the dict directly
images['rain_tk'] = ImageTk.PhotoImage(image,name='rain')
#make and return the label,in case you want to grid_forget it or change the image
label = tk.Label(root,image='rain') #instead of image=images['rain_tk']
label.grid(row=row,column=column)
return label
#you can easily display this wherever you want by filling in the row and column arguments
#as an example,this would be displayed at row1 column2
rain_lbl = display_rain(1,2)
root.mainloop()
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