为什么在尝试移动按钮时.grid给我一个错误

如何解决为什么在尝试移动按钮时.grid给我一个错误

import time
import tkinter as tk
from tkinter import scrolledtext

win = tk.Tk()

win.title("My First Game")
win.configure(bg="black")
win.geometry("640x400")

label = tk.Label(win,text="test",fg="red",bg="black").pack()

canvas1 = tk.Canvas(win,width=130,height=20)
canvas1.pack()

entry1 = tk.Entry(win,font="Helvetica 10")
canvas1.create_window(65,10,window=entry1)
entry1.insert(0,"Type here")


def shortcut():
    Shortcut = tk.Label(win,bg="black",text="test2")
    Shortcut.pack()


button1 = tk.Button(win,text="Enter",command=shortcut)
button1.pack()

exit_button = tk.Button(win,text="Quit",padx=4,pady=2,command=quit)
exit_button.pack()
exit_button.grid(row=0,column=2)


win.mainloop()

这为什么给我一个错误？我在一个只有黑屏和按钮的单独项目中尝试过，效果很好。但是当我把它放在上面的代码中不起作用

line 42,in <module> exit_button.grid(row=0,column=2)
_tkinter.TclError: cannot use geometry manager grid inside . which already has slaves managed by pack

解决方法

正如@ 10Rep在评论中提到的那样-您可以删除grid()来解决错误问题。

import tkinter as tk

# --- functions ---

def shortcut():
    shortcut = tk.Label(win,text="test2")
    shortcut.pack()

# --- main ---

win = tk.Tk()

label = tk.Label(win,text="test")
label.pack()

canvas1 = tk.Canvas(win) #,width=130,height=20)
canvas1.pack()

entry1 = tk.Entry(canvas1)
canvas1.create_window(0,window=entry1,anchor='nw')
entry1.insert(0,"Type here")

button1 = tk.Button(win,text="Enter",command=shortcut)
button1.pack()

exit_button = tk.Button(win,text="Quit",command=win.destroy)
exit_button.pack()

win.mainloop()

但是我希望您使用grid()将两个按钮排成一行。 问题是您无法在一个窗口/帧中混合使用pack()和grid()，但我看到两种解决方案：

首先是仅使用grid()来组织所有小部件

import tkinter as tk

# --- functions ---

def shortcut():
    shortcut = tk.Label(win,text="test2")
    shortcut.grid(row=3,column=0,columnspan=2)

# --- main ---

win = tk.Tk()

label = tk.Label(win,text="test")
label.grid(row=0,columnspan=2)

canvas1 = tk.Canvas(win) #,height=20)
canvas1.grid(row=1,columnspan=2)

entry1 = tk.Entry(canvas1)
canvas1.create_window(0,command=shortcut)
button1.grid(row=2,column=0)

exit_button = tk.Button(win,command=win.destroy)
exit_button.grid(row=2,column=1)

win.mainloop() 

第二种方法是使用Frame将pack()（使用grid()）和按钮放置在该框架内

import tkinter as tk

# --- functions ---

def shortcut():
    shortcut = tk.Label(win,"Type here")

# - frame with grid -

f = tk.Frame(win)
f.pack()

button1 = tk.Button(f,command=shortcut)
button1.grid(row=0,column=0)

exit_button = tk.Button(f,command=win.destroy)
exit_button.grid(row=0,column=1)

# -

win.mainloop()

或使用pack(side=...)

import tkinter as tk

# --- functions ---

def shortcut():
    shortcut = tk.Label(win,"Type here")

# - frame with pack(side=...) -

f = tk.Frame(win)
f.pack()

button1 = tk.Button(f,command=shortcut)
button1.pack(side='left')

exit_button = tk.Button(f,command=win.destroy)
exit_button.pack(side='left')

# -

win.mainloop()