如何解决根据条件将节点分组在一起，并使用Schematron进行验证
我正在使用Schematron编写规则以验证以下数据。要求是验证患者在过去12个月中是否至少有过一次遭遇。如果每个患者有多次遭遇，请使用最后一次遭遇。
<root>
<entry>
<resource>
<resourceType>Encounter</resourceType>
<subject>
<id>Patient/12345</id>
</subject>
<encounterDate>2018-04-10T10:00:00</encounterDate>
</resource>
</entry>
<entry>
<resource>
<resourceType>Encounter</resourceType>
<subject>
<id>Patient/abcde</id>
</subject>
<encounterDate>2020-04-10T10:00:00</encounterDate>
</resource>
</entry>
<entry>
<resource>
<resourceType>Encounter</resourceType>
<subject>
<id>Patient/abcde</id>
</subject>
<encounterDate>2019-05-10T10:00:00</encounterDate>
</resource>
</entry>
</root>
以上数据应通过验证，因为最近的一次遭遇不到一年。 我想知道的是，如果我编写了一个按患者ID将遇到的事件分组在一起的模板，是否可以将该模板传递给规则上下文？如果没有，还有其他方法吗？ 我对xslt和Schematron都是全新的，到目前为止，这是我所拥有的：
<schema xmlns="http://purl.oclc.org/dsdl/schematron" >
<pattern>
<key name="patientId" match="entry" use="/resouce/subject/id/text()"/>
<template name="dateByPatient" match="entry">
<root>
<for-each select="resource/subject/id">
<patient >
<for-each select="key('patientId',text())">
<effectiveDateTime><value-of select="./resource/encounterDate"/></effectiveDateTime>
</for-each>
</patient>
</for-each>
</root>
</template>
<let name="template">
<dateByPatient/>
</let>
<let name="latest">
<root>
<for-each select="$template/root/patient">
<patient >
<sort select="effectiveDateTime" order="descending" />
<if test="position() = 1">
<effectiveDateTime><value-of select="effectiveDateTime" /></effectiveDateTime>
</if>
</patient>
</for-each>
</root>
</let>
<rule context="$latest/root/patient/effectiveDateTime">
<let name="days" value="days-from-duration(fn:current-dateTime() - xs:dateTime(text()))" />
<assert test="days-from-duration(fn:current-dateTime() - xs:dateTime(text())) < 365">
Encounter date more than a year : <value-of select="$days" /> days
</assert>
</rule>
</pattern>
</schema>
解决方法
有了XSLT 3基础，您可以使用
<?xml version="1.0" encoding="UTF-8"?>
<sch:schema xmlns:sch="http://purl.oclc.org/dsdl/schematron" queryBinding="xslt3"
xmlns:sqf="http://www.schematron-quickfix.com/validator/process">
<sch:ns prefix="map" uri="http://www.w3.org/2005/xpath-functions/map"/>
<sch:pattern>
<sch:rule context="root">
<sch:let name="groups"
value="let $encounter-resources := entry/resource[resourceType = 'Encounter']
return map:merge(
$encounter-resources
!
map {
data(subject/id) : xs:dateTime(encounterDate)
},map { 'duplicates' : 'combine' }
)"/>
<sch:assert
test="every $patient in map:keys($groups)
satisfies
(current-dateTime() - max($groups($patient)))
lt xs:dayTimeDuration('P365D')">At least one patient with latest encounter more than a year ago.</sch:assert>
</sch:rule>
</sch:pattern>
</sch:schema>
或者输出更多详细信息，并且仅处理Encounter类型的资源：
<?xml version="1.0" encoding="UTF-8"?>
<sch:schema xmlns:sch="http://purl.oclc.org/dsdl/schematron" queryBinding="xslt3"
xmlns:sqf="http://www.schematron-quickfix.com/validator/process">
<sch:ns prefix="map" uri="http://www.w3.org/2005/xpath-functions/map"/>
<sch:pattern>
<sch:rule context="root">
<sch:let name="groups"
value="let $encounter-resources := entry/resource[resourceType = 'Encounter']
return map:merge(
$encounter-resources
!
map {
data(subject/id) : xs:dateTime(encounterDate)
},map { 'duplicates' : 'combine' }
)"/>
<sch:let name="failing-patients"
value="map:keys($groups)[(current-dateTime() - max($groups(.))) gt xs:dayTimeDuration('P365D')]"/>
<sch:report
test="exists($failing-patients)">Patients <sch:value-of select="$failing-patients"/> with latest encounter more than a year ago.</sch:report>
</sch:rule>
</sch:pattern>
</sch:schema>
我认为您不能像代码尝试那样随意地混合使用Schematron和XSLT，您需要设置一个XProc管道以使用p:xslt对原始输入进行分组，然后执行一个验证步骤以进行验证Schematron。
对于使用node-schematron运行第二个示例时遇到的问题，它使用了似乎不支持XPath 3.1 sort函数的XPath实现，node-schematron也无法将映射作为中间结果来处理Schematron变量，因此似乎只能将全部填充到一个变量表达式中；两个示例起作用：
<sch:schema xmlns:sch="http://purl.oclc.org/dsdl/schematron" queryBinding="xslt3"
xmlns:sqf="http://www.schematron-quickfix.com/validator/process">
<sch:ns prefix="map" uri="http://www.w3.org/2005/xpath-functions/map"/>
<sch:pattern>
<sch:rule context="root">
<sch:let name="failing-patients"
value="let $encounter-resources := entry/resource[resourceType = 'Encounter'],$groups := map:merge(
$encounter-resources
!
map {
data(subject/id) : xs:dateTime(encounterDate)
},map { 'duplicates' : 'combine' }
)
return map:keys($groups)[(current-dateTime() - max($groups(.))) gt xs:dayTimeDuration('P365D')]"/>
<sch:report
test="exists($failing-patients)">Patients <sch:value-of select="$failing-patients"/> with latest encounter more than a year ago.</sch:report>
</sch:rule>
</sch:pattern>
</sch:schema>
或
<sch:schema xmlns:sch="http://purl.oclc.org/dsdl/schematron" queryBinding="xslt3"
xmlns:sqf="http://www.schematron-quickfix.com/validator/process">
<sch:ns prefix="map" uri="http://www.w3.org/2005/xpath-functions/map"/>
<sch:pattern>
<sch:rule context="root">
<sch:let name="failing-patients"
value="let
$encounter-resources := entry/resource[resourceType = 'Encounter'],$groups := fold-left(
$encounter-resources,map{},function($m,$e) {
map:put(
$m,data($e/subject/id),max((xs:dateTime($e/encounterDate),map:get($m,data($e/subject/id))))
)
})
return map:keys($groups)[(current-dateTime() - $groups(.)) gt xs:dayTimeDuration('P365D')]"/>
<sch:report test="exists($failing-patients)">Patients <sch:value-of
select="$failing-patients"/> with latest encounter more than a year
ago.</sch:report>
</sch:rule>
</sch:pattern>
</sch:schema>
如果您需要失败的断言，则将sch:report替换为
<sch:assert
test="empty($failing-patients)">Patients <sch:value-of select="$failing-patients"/> with latest encounter more than a year ago.</sch:assert>
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