如何解决SQL,嵌套选择
我正在学习如何在另一个选择中进行选择,并且提供了解决方案,但是时间太长了。这个解决方案可以缩短吗?
我想要这个查询:
select continent,name
from world x
where name =
(SELECT min(name) FROM world
WHERE continent = 'Africa')
or name =
(SELECT min(name) FROM world
WHERE continent = 'Asia')
or name =
(SELECT min(name) FROM world
WHERE continent = 'Caribbean')
or name =
(SELECT min(name) FROM world
WHERE continent = 'Eurasia')
or name =
(SELECT min(name) FROM world
WHERE continent = 'Europe')
or name =
(SELECT min(name) FROM world
WHERE continent = 'north America')
or name =
(SELECT min(name) FROM world
WHERE continent = 'Oceania')
or name =
(SELECT min(name) FROM world
WHERE continent = 'South America')
order by continent
limit 8
以这样的方式写:
SELECT continent,name,area FROM world x
WHERE area >= ALL
(SELECT max(area) FROM world y
WHERE y.continent = x.continent
AND area > 0)
任何人都可以解释第二个查询,它如何工作,谢谢。
解决方法
尝试一下
SELECT Continent,Name
FROM World x
WHERE NAME IN (SELECT MIN(Name) FROM world WHERE Continent IN ('Africa','Asia','Caribbean','Eurasia','Europe','North America','Oceania','South America') GROUP BY Continent)
ORDER BY Continent
LIMIT 8
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