SSRS表达式在行和列中拆分字符串

如何解决SSRS表达式在行和列中拆分字符串

我正在使用sql Server 2008报表服务。我必须尝试在表达式的同一行中的不同列中拆分字符串值，但是我无法获得例外的输出。我提供了输入和输出详细信息。我必须按空格（“”）和（“-”）分割值。

输入：

示例1：

ASY-LOS,SLD,ME,A1,A5,J4A,J4B,J4O,J4P,J4S,J4T,J7,J10,J2A,J2,S2,S3,S3T,S3S,E2,E2F,E6,T6,8,SB1,E1S,OTH AS2-J4A,J1O,T8,E4,OTH

示例2：

A1 A2 A3 A5 D2 D3 D6 E2 E4 E5 E6 EOW LH LL LOS OTH P8 PH PL PZ-1,2,T1,T2,T3 R2-C,E,A RH RL S1 S2-D S3

输出应为：

谢谢。

解决方法

我写这篇文章是在报告中看到您对必须这样做的评论之前。如果您可以解释为什么无法在数据集查询中执行此操作，那么可能有解决方法。

无论如何，这是一种使用SQL的方法

DECLARE @t table (RowN int identity (1,1),sample varchar(500))
INSERT INTO @t (sample) SELECT 'ASY-LOS,SLD,ME,A1,A5,J4A,J4B,J4O,J4P,J4S,J4T,J7,J10,J2A,J2,S2,S3,S3T,S3S,E2,E2F,E6,T6,8,SB1,E1S,OTH AS2-J4A,J1O,T8,E4,OTH'
INSERT INTO @t (sample) SELECT 'A1 A2 A3 A5 D2 D3 D6 E2 E4 E5 E6 EOW LH LL LOS OTH P8 PH PL PZ-1,2,T1,T2,T3 R2-C,E,A RH RL S1 S2-D S3'

drop table if exists #s1
SELECT RowN,sample,SampleIdx = idx,SampleValue = [Value]
into #s1
from @t t
 CROSS APPLY 
 spring..fn_Split(sample,' ') as x 
 
drop table if exists #s2
SELECT 
    s1.*,s2idx = Idx,s2Value = [Value]
    into #s2
    FROM #s1 s1
    CROSS APPLY spring..fn_Split(SampleValue,'-')

SELECT SampleKey = [1],Output = [2]  FROM #s2
PIVOT (
        MAX(s2Value)
        FOR s2Idx IN ([1],[2])
) p

这产生了以下结果

---

如果您没有拆分功能，请使用以下脚本创建我使用的脚本

---

CREATE FUNCTION [dbo].[fn_Split]

/* Define I/O parameters WARNING! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE! */
    (@pString VARCHAR(8000),@pDelimiter CHAR(1)

    )
RETURNS TABLE
    WITH SCHEMABINDING
AS

RETURN

/*"Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000: enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
        SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
        SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
        )--10E+1 or 10 rows,E2(N) AS (SELECT 1 FROM E1 a,E1 b)--10E+2 or 100 rows,E4(N) AS (SELECT 1 FROM E2 a,E2 b)--10E+4 or 10,000 rows max
    
    /* This provides the "base" CTE and limits the number of rows right up front
    for both a performance gain and prevention of accidental "overruns" */,cteTally(N) AS (
        SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
        FROM E4
        )
    
    /* This returns N+1 (starting position of each "element" just once for each delimiter) */,cteStart(N1) AS (
        SELECT 1 UNION ALL
        SELECT t.N + 1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
        )
    
    /* Return start and length (for use in SUBSTRING later) */,cteLen(N1,L1) AS (
        SELECT s.N1,ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0) - s.N1,8000)
        FROM cteStart s
        )

/* Do the actual split.
The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found. */
SELECT
     idx = ROW_NUMBER() OVER (ORDER BY l.N1),value = SUBSTRING(@pString,l.N1,l.L1)
FROM cteLen l