创建多个xml文件并将其导出为一个zip文件的最佳方法是什么？

如何解决创建多个xml文件并将其导出为一个zip文件的最佳方法是什么？

我的项目位于ASP.NET MVC中，现在我正在使用Razor引擎服务（RazorEngineservice.runcompile）创建多个XML文件，并将其作为单个Zip文件导出。

但是问题是，当我们每次传递模型对象以处理模板并将其作为单独的XML文件返回并完成整个操作时，整个内容需要花费更多的时间来完成（10个对象几乎需要40秒）导出。

我当前的方法有什么问题吗？或者我现在是否正确地做到了？如果我在这种方法上有任何错误，请指导我。

private FileInfo Export(List<Model> modelList)
  {
        string timeStr = Datetime.Now.ToString();
        string archiveFileName = "Main.zip";
        string archivePath = Path.Combine(_reportFolderPath,archiveFileName);

        using (ZipArchive archive = ZipFile.Open(archivePath,ZipArchiveMode.Create))
    {
        foreach (var list in modelList)
        {
            string fileName = model.name + model.Id;
            string filePath = GetModelExport(list,fileName,timeStr);
            archive.CreateEntryFromFile(filePath,fileName + ".xml");
        }
        archive.dispose();
    }
    return new FileInfo(archivePath);
}

private string GetModelExport(Model model,string fileName,string timeStr)
{
    var processedTemplate = Processtemplate(model,TemplateName,TemplateKey);
    string reportFilelName = fileName + "_" + timeStr + ".xml";
    string filePath = Path.Combine(_reportFolderPath,reportFilelName);

    using (var file = new StreamWriter(filePath))
    {
        file.Write(processedTemplate);
    }
    return filePath;
}

private string Processtemplate(Model model,string templateName,string templateKey)
    {
        var templateFilePath = Path.Combine(_reportTemplateFolder,templateName);
        return ReportUtils.Processtemplate(templateFilePath,templateKey,model);
    }
public static string Processtemplate(string templatePath,string templateKey,object model = null)
{
    var templateService = RazorEngineservice.Create();
    var result = templateService.runcompile(File.ReadAllText(templatePath),null,model);

    return result;
}

解决方法

您的某些代码丢失了，所以我看不到整个图片，这就是我将从..... gd运气开始的事情。

public class HolderTempName 
{
    private TemplateService _templateService;
    private Dictionary<string,string> _templateContainer;
    
    public HolderTempName()
    {
        //this will save creating this everytime
        _templateService = RazorEngineService.Create();
        
        //this will hold the template so it does not have to fetch on each loop,//if the same template is used.
        _templateContainer = new Dictionary<string,string>();
    }


    //you will need to tweeek this to get the type out 
    private string GetTemplate(string templateName,templatePath)
    {
        if(!_templateContainer.Conatains(templateName))
        {
            var text = File.ReadAllText(templatePath);
            _templateContainer[templateName]  = text;
        }
        return _templateContainer[templateName];
    }


    private FileInfo Export(List<Model> modelList)
    {
        string timeStr = Datetime.Now;
        string archiveFileName = "Main.zip";
        string archivePath = Path.Combine(_reportFolderPath,archiveFileName);


        using (ZipArchive archive = ZipFile.Open(archivePath,ZipArchiveMode.Create))
        {
            foreach (var item in modelList)
            {
                var templateFilePath = Path.Combine(_reportTemplateFolder,TemplateName); //<--TemplateName seems like a local private
                //these should come from where cant see where...
                var template = GetTemplate( TemplateName,templateFilePath)
                
                string modelResponse  = ProcessModel(item,template,TemplateKey ); //<-- why is not passing in the template
                //step 2; 
                //making this above done in parrell and then add aync,but before all that measure what is taking time
                
                string pathname = MakeFileName(_reportFolderPath,reportFilelName,timeStr);
                SaveToDisk(pathname,modelResponse);
                
                string fileName = model.name + model.Id;
                archive.CreateEntryFromFile(filePath,fileName + ".xml");
            }
            archive.Dispose();
        }
        return new FileInfo(archivePath);
    }

    private string MakeFileName(string path,string filename,string tStamp)
    {
        string reportFilelName = fileName + "_" + timeStr + ".xml";
        string filePath = Path.Combine(_reportFolderPath,reportFilelName);
        return filePath;
    }

    private void SaveToDisk(string filePath,string content)
    {
        using (var file = new StreamWriter(filePath))
        {
            file.Write(processedTemplate);
        }
    }
    
    public static string ProcessTemplate(object model,string template,templateKey)
    {
        var result = templateService.RunCompile(template,templateKey,null,model);
        return result;
    }
}