如何解决Impala SQL:合并具有重叠日期的行不支持WHERE EXISTS和递归CTE
select min(StartDate) as StartDate ,max(EndDate) as EndDate
from (select StartDate,EndDate
,count (is_gap) over
(
order by StartDate,ID
) as range_id
from (select ID,StartDate,EndDate
,case
when max (EndDate) over
(
order by StartDate,ID
rows between unbounded preceding
and 1 preceding
) < StartDate
then true
end as is_gap
from t
) t
) t
group by range_id
order by StartDate
;
+------------+------------+
| startdate | enddate |
+------------+------------+
| 2017-01-01 | 2017-04-01 |
| 2017-05-05 | 2017-08-31 |
| 2017-10-01 | 2017-10-05 |
| 2017-11-01 | 2017-12-25 |
+------------+------------+
解决方法
我正在尝试在Impala SQL的表中合并具有重叠日期间隔的行。但是,Impala不支持我找到的解决方案。存在和递归CTE。
我将如何在Impala中为此编写查询?
Table: @T
ID StartDate EndDate
1 20170101 20170201
2 20170101 20170401
3 20170505 20170531
4 20170530 20170531
5 20170530 20170831
6 20171001 20171005
7 20171101 20171225
8 20171105 20171110
Required Output:
StartDate EndDate
20170101 20170401
20170505 20170831
20171001 20171005
Impala不支持我尝试实现的示例:
SELECT
s1.StartDate,MIN(t1.EndDate) AS EndDate
FROM @T s1
INNER JOIN @T t1 ON s1.StartDate <= t1.EndDate
AND NOT EXISTS(SELECT * FROM @T t2
WHERE t1.EndDate >= t2.StartDate AND t1.EndDate < t2.EndDate)
WHERE NOT EXISTS(SELECT * FROM @T s2
WHERE s1.StartDate > s2.StartDate AND s1.StartDate <= s2.EndDate)
GROUP BY s1.StartDate
ORDER BY s1.StartDate
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