如何解决如何将JSON数组转换为Java列表我正在使用svenson
您不能将此json转换为,List
但可以将其转换为Map
。
看到你的json String
:
...
"Example": [
{
"foo": "a1",
"bar": "b1",
"fubar": "c1"
},
{
"foo": "a2",
"bar": "b2",
"fubar": "c2"
},
...
]
}
试试这个:
parser.addTypeHint("Example[]", Example.class);
Map<String,List<Example>> result1 = parser.parse(Map.class, json);
for (Entry<String, List<Example>> entry : result1.entrySet()) {
for (Example example : entry.getValue()) {
System.out.println("VALUE :->"+ example.getFoo());
}
}
的完整代码Example
:
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import org.svenson.JSONParser;
public class Test {
public static void main(String[] args) {
JSONParser parser = new JSONParser();
parser.addTypeHint(".Example[]", Example.class);
String json = "{" + "\"Example\": [" + "{" + "\"foo\": \"a1\","
+ "\"bar\": \"b1\"," + "\"fubar\": \"c1\"" + "}," + "{"
+ "\"foo\": \"a2\"," + "\"bar\": \"b2\"," + "\"fubar\": \"c2\""
+ "}," + "{" + "\"foo\": \"a3\"," + "\"bar\": \"b3\","
+ "\"fubar\": \"c3\"" + "}" + "]" + "}\"";
parser.addTypeHint("Example[]", Example.class);
Map<String, List<Example>> result1 = parser.parse(Map.class, json);
for (Entry<String, List<Example>> entry : result1.entrySet()) {
for (Example example : entry.getValue()) {
System.out.println("VALUE :->" + example.getFoo());
}
}
}
}
public class Example {
private String foo;
private String bar;
private String fubar;
public Example(){}
public void setFoo(String foo) {
this.foo = foo;
}
public String getFoo() {
return foo;
}
public void setBar(String bar) {
this.bar = bar;
}
public String getBar() {
return bar;
}
public void setFubar(String fubar) {
this.fubar = fubar;
}
public String getFubar() {
return fubar;
}
}
:
VALUE :->a1
VALUE :->a2
VALUE :->a3
解决方法
我试图将多个相同类型的对象转换为List
Java。例如,我的json是:
{
"Example": [
{
"foo": "a1","bar": "b1","fubar": "c1"
},{
"foo": "a2","bar": "b2","fubar": "c2"
},{
"foo": "a3","bar": "b3","fubar": "c3"
}
]
}
我有一堂课:
public class Example {
private String foo;
private String bar;
private String fubar;
public Example(){};
public void setFoo(String f){
foo = f;
}
public void setBar(String b){
bar = b;
}
public void setFubar(String f){
fubar = f;
}
...
}
我希望能够将获取的json字符串转换为Example
对象列表。我想做这样的事情:
JSONParser parser = new JSONParser();
parser.addTypeHint(".Example[]",Example.class);
List<Example> result = parser.parse(List.class,json);
这样做我得到一个错误:
Cannot set property Example on class java.util.ArrayList
版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。