如何解决如何使用Java获取xml节点的属性值
由于您的问题较为笼统,请尝试使用Java中提供的XML解析器来实现。如果您特定于解析器,请在此处更新您尝试过的代码
<?xml version="1.0" encoding="UTF-8"?>
<ep>
<source type="xml">TEST</source>
<source type="text"></source>
</ep>
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document doc = builder.parse("uri to xmlfile");
XPathFactory xPathfactory = XPathFactory.newInstance();
XPath xpath = xPathfactory.newXPath();
XPathExpression expr = xpath.compile("//ep/source[@type]");
NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
for (int i = 0; i < nl.getLength(); i++)
{
Node currentItem = nl.item(i);
String key = currentItem.getAttributes().getNamedItem("type").getNodeValue();
System.out.println(key);
}
解决方法
我有一个看起来像这样的xml:
{ <xml><ep><source type="xml">...</source><source type="text">..</source></ep></xml>}
在这里,我想检索类型为属性的“源类型”的值。
我曾这样尝试过,但无法正常工作:
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("D:/workspace1/ereader/src/main/webapp/configurations/config.xml");
System.out.println(dDoc);
XPath xPath = XPathFactory.newInstance().newXPath();
Node node = (Node) xPath.evaluate("//xml/source/@type/text()",dDoc,XPathConstants.NODE);
System.out.println(node);
} catch (Exception e) {
e.printStackTrace();
我也尝试过这个:
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
InputSource is = new InputSource(new StringReader("config.xml"));
Document doc = builder.parse(is);
NodeList nodeList = doc.getElementsByTagName("source");
for (int i = 0; i < nodeList.getLength(); i++) {
Node node = nodeList.item(i);
if (node.hasAttributes()) {
Attr attr = (Attr) node.getAttributes().getNamedItem("type");
if (attr != null) {
String attribute= attr.getValue();
System.out.println("attribute: " + attribute);
}
}
}
请帮助我!!
在此先感谢Varsha。
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