微信公众号搜"智元新知"关注
微信扫一扫可直接关注哦!

golang中的接口和整数比较

我不明白为什么第一个结果是假的,而第二个结果是真的.

任何帮助将不胜感激.

func main() {
    var i interface{}

    i = uint64(0)
    fmt.Println("[1] ",reflect.TypeOf(i),i == 0)

    i = 0
    fmt.Println("[2] ",i == 0)

    var n uint64 = 32
    fmt.Println("[3] ",reflect.TypeOf(n),n == 32) 
}

// result
// [1]  uint64 false
// [2]  int true
// [3]  uint64 true

在这里尝试Go playground

因为0是一个非类型化常量,其认类型是int,而不是uint64,并且在与接口进行比较时,您要比较的东西必须是相同的类型,并且它们被视为相同的相同值.

https://golang.org/ref/spec#Comparison_operators

The equality operators == and != apply to operands that are comparable. The ordering operators <,<=,>,and >= apply to operands that are ordered. These terms and the result of the comparisons are defined as follows:

A value x of non-interface type X and a value t of interface type T are comparable when values of type X are comparable and X implements T. They are equal if t’s dynamic type is identical to X and t’s dynamic value is equal to x.

原文地址:https://www.jb51.cc/go/186939.html

版权声明:本文内容由互联网用户自发贡献,该文观点与技术仅代表作者本人。本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容, 请发送邮件至 dio@foxmail.com 举报,一经查实,本站将立刻删除。

相关推荐