我从openfire中获取历史记录,通过在开火中安装打开的fire plugin并尝试这个代码.
let iq1 = DDXMLElement(name: "iq")
iq1.addAttribute(withName: "type",stringValue: "get")
iq1.addAttribute(withName: "id",stringValue: "0")
let retrieve = DDXMLElement(name: "retrieve",xmlns: "urn:xmpp:archive")
retrieve?.addAttribute(withName: "with",stringValue: "raman@ip-172-31-53-77.ec2.internal")
let set = DDXMLElement(name: "set",xmlns: "http://jabber.org/protocol/rsm")
let max = DDXMLElement(name: "max",stringValue: "50")
iq1.addChild(retrieve!)
retrieve?.addChild(set!)
set?.addChild(max)
stream?.send(iq1 )
现在我没有从双方得到历史.这是我得到的结果.
<iq xmlns="jabber:client" type="result" id="0" to="bentick@ip-172-31-53-77.ec2.internal/5qsinh1syg"> <chat xmlns="urn:xmpp:archive" with="raman@ip-172-31-53-77.ec2.internal" start="2017-02-07T06:28:33.691Z"> <from secs="0"> <body>hello</body> </from> <from secs="405"> <body>hiii</body> </from> <from secs="580"> <body>hey</body> </from> <from secs="599"> <body>HooooE</body> </from> <from secs="628"> <body>hOo</body> </from> <from secs="907"> <body>Raman here</body> </from> <from secs="931"> <body>Raman here ONE</body> </from> <from secs="1273"> <body>Raman here</body> </from> <from secs="1558"> <body> Raman from SPark </body> </from> <from secs="1571"> <body> Raman from SPark One</body> </from> <from secs="1782"> <body>Raman from SPark </body> </from> <from secs="2651"> <body>Raman FiVE</body> </from> <from secs="2810"> <body>Raman Three</body> </from> <from secs="2810"> <body>Raman FOur</body> </from> <from secs="3534"> <body>RAMAN SIX</body> </from> <from secs="4105"> <body>Raman OKK</body> </from> <from secs="4113"> <body>OKKK l</body> </from> <from secs="4130"> <body>UST</body> </from> <set xmlns="http://jabber.org/protocol/rsm"> <first index="0">0</first> <last>17</last> <count>18</count> </set> </chat> </iq>
这是RAMAN不是BENTICK的所有消息,因为这两个用户参与聊天,同时获得历史,我只得到RAMAN的消息.不是BENTICk
如何从双方用户获取历史.
请帮忙.
解决方法
我已经实现了相同的方式来通过发送给定的iq来获取消息
我得到了正确的结果.
我得到了正确的结果.
let iQ = DDXMLElement.element(withName: "iq") as! DDXMLElement
iQ.addAttribute(withName: "type",stringValue: "get")
iQ.addAttribute(withName: "id",stringValue: (xmppHandler.xmppStream?.generateUUID())!)
let retrieve = DDXMLElement(name: "retrieve",xmlns: "urn:xmpp:archive")
retrieve?.addAttribute(withName: "with",stringValue: "\(JID!)@\(Utility.hostname)")
let set = DDXMLElement.element(withName: "set") as! DDXMLElement
set.addAttribute(withName: "xmlns",stringValue: "http://jabber.org/protocol/rsm")
let max = DDXMLElement.element(withName: "max") as! DDXMLElement
max.stringValue = "10"
max.addAttribute(withName:"xmlns",stringValue: "http://jabber.org/protocol/rsm")
iQ.addChild(retrieve!)
retrieve?.addChild(set)
set.addChild(max as DDXMLNode)
xmppHandler.xmppStream?.send(iQ)
<iq type="get" id="7705EEC5-3385-42D4-B748-B39C204ADB90"><retrieve xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181"><set xmlns="http://jabber.org/protocol/rsm"><max xmlns="http://jabber.org/protocol/rsm">10</max></set></retrieve></iq>
响应
<iq xmlns="jabber:client" type="result" id="7705EEC5-3385-42D4-B748-B39C204ADB90" to="0509503847@192.168.2.181/Smack">
<chat xmlns="urn:xmpp:archive" with="0544008296@192.168.2.181" start="2017-02-28T09:55:27.068Z">
<from secs="0" jid="0544008296@192.168.2.181">
<body>Hiii rajeev</body>
</from>
<to secs="52">
<body>Hi
How r u</body>
</to>
<from secs="15" jid="0544008296@192.168.2.181"><body>I am good</body></from>
<to secs="8"><body>What abt u</body></to>
<to secs="169"><body>Hello testing chat</body></to>
<from secs="10" jid="0544008296@192.168.2.181"><body>Good</body></from>
<from secs="5" jid="0544008296@192.168.2.181"><body>Continue </body></from>
<to secs="834"><body>Ok
</body></to>
<to secs="8"><body>Nice chat
</body></to>
<from secs="232" jid="0544008296@192.168.2.181"><body>Heelo</body></from>
<set xmlns="http://jabber.org/protocol/rsm"><first index="0">0</first> <last>9</last><count>574</count></set></chat></iq>
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