ios – Swift Timer.scheduledTimer()不起作用

我的 swift应用程序中有两个视图.我正在执行如下的segue.

ViewController.swift —————–> GameViewController.swift

加载GameViewController时,一个值数组也从ViewController.swift传递给GameViewController.swift

应该在GameViewController.swift中初始化一个计时器

我试图初始化一个计时器并通过它调用一个方法,但它不起作用.

以下是我的代码片段.

ViewController.swift

func signIn(difficultyLvl:String){
    let username = usernameTxt.text
    let password = passwordTxt.text

    let url = URL(string: "http://192.168.1.106/speed/scoreBoardController.PHP?username="+username!+"&password="+password!+"&action=SIGNIN")

    let task = URLSession.shared.dataTask(with: url!) {(data,response,error) in
        let isPassed = String(data: data!,encoding:.utf8)?.trimmingCharacters(in: CharacterSet.whitespacesAndNewlines)

        var gameViewControllerParams = [Int: [String: String]]()
        gameViewControllerParams[0] = ["userId" : isPassed!]
        gameViewControllerParams[1] = ["difficultyLvl" : difficultyLvl]

        if(isPassed != "null"){
            self.performSegue(withIdentifier: "gotoGame",sender: gameViewControllerParams)
        }
    }

    task.resume()
}

GameViewController.swift

class GameViewController: UIViewController {

    var gameViewControllerParams = [Int: [String: String]]()

    override func viewDidLoad() {
        super.viewDidLoad()

        let _ = Timer.scheduledTimer(timeInterval: 1.0,target:self,selector: #selector(self.setCalculationLs),userInfo:nil,repeats: true)
    }

    func setCalculationLs(){
        print("Timing")
    }

}

解决方法

定时器不适用于后台队列(没有一些涉及创建运行循环或在现有运行循环上手动调度它的手段).但是你绝不应该从主队列以外的任何东西发起任何UI更新.

因此,由于您从URLSession完成闭包(在后台队列上运行)调用performSegue,它实际上也在后台队列中运行viewDidLoad.因此,计划定时器的尝试失败.要解决此问题,您必须手动将performSegue代码分派到主队列：

let task = URLSession.shared.dataTask(with: url!) { data,error in
    ...

    if isPassed != "null" {
        dispatchQueue.main.async {
            self.performSegue(withIdentifier: "gotoGame",sender: ...)
        }
    }
}

如果您不确定某些代码是否在主队列上运行,请参阅the documentation.或者您可以使用调度前提条件：

dispatchPrecondition(condition: .onQueue(.main))

这样,如果您不小心从后台队列中调用了代码,它将(在调试版本中)停止应用程序.

与您当前的问题无关,但另外,为了避免计时器和视图控制器之间的强引用周期,您通常希望保留对计时器的引用,以便在视图消失时使其无效(例如,创建计时器) viewDidAppear并在viewDiddisappear中删除它.否则你可以在解雇后最终保留GameViewController,例如：

class GameViewController: UIViewController {

    var timer: Timer?

    override func viewDidAppear(_ animated: Bool) {
        super.viewDidAppear(animated)

        timer = Timer.scheduledTimer(timeInterval: 1.0,selector: #selector(setCalculationLs),userInfo: nil,repeats: true)
    }

    override func viewDiddisappear(_ animated: Bool) {
        super.viewDiddisappear(animated)

        timer?.invalidate()
    }

    func setCalculationLs() {
        print("Tick")
    }
}

或者在iOS 10中,您可以使用基于块的变体,对自身的弱引用,以及在deinit中无效：

class GameViewController: UIViewController {

    var timer: Timer?

    override func viewDidLoad() {
        super.viewDidLoad()

        timer = Timer.scheduledTimer(withTimeInterval: 1.0,repeats: true) { [weak self] timer in
            self?.setCalculationLs()
        }
    }

    deinit {
        timer?.invalidate()
    }

    func setCalculationLs() {
        print("Tick")
    }

}

原文地址：https://www.jb51.cc/iOS/331121.html

ios – Swift Timer.scheduledTimer()不起作用

解决方法

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