ios – Swift的编码/解码枚举(Xcode 6.1)

参见英文答案 > How do I encode enum using NSCoder in swift?3个
我有

var priority : Priority! = Priority.defaultPriority

func encodeWithCoder(aCoder: NSCoder) {
        aCoder.encodeInteger(priority.toRaw(),forKey: "priority") //toRaw may not yield the result I am expecting
    }

    required init(coder aDecoder: NSCoder) {
        priority = aDecoder.decodeIntegerForKey("priority") //complaining about conflicting types
    }

枚举如下：

enum Priority : Int {
        case defaultPriority = 0
        case lowPriority = 1
        case mediumPriority = 2
        case highPriority = 3
    }

编码/解码这个的最佳方法是什么？

解决方法

Priority.init(rawValue :)应该可以工作.

func encodeWithCoder(aCoder: NSCoder) {
    aCoder.encodeInteger(priority.rawValue,forKey: "priority")
}

required init(coder aDecoder: NSCoder) {
    priority = Priority(rawValue: aDecoder.decodeIntegerForKey("priority"))
}

原文地址：https://www.jb51.cc/iOS/332315.html