您好我从我的服务器成功获得响应.我需要访问我的应用程序中的服务器发送的user_id.
检查我的代码:
NSURLSessionConfiguration *defaultConfigObject = [NSURLSessionConfiguration defaultSessionConfiguration];
NSURLSession *defaultSession = [NSURLSession sessionWithConfiguration: defaultConfigObject delegate: nil delegateQueue: [NSOperationQueue mainQueue]];
NSURL * url = [NSURL URLWithString:@"my url"];
NSMutableuRLRequest * urlRequest = [NSMutableuRLRequest requestWithURL:url];
Nsstring * params=[[Nsstring alloc]initWithFormat:@"mobile=%@",[self.reqnum text ]];
NSLog(@"%@",params);
[urlRequest setHTTPMethod:@"POST"];
[urlRequest setHTTPBody:[params dataUsingEncoding:NSUTF8StringEncoding]];
NSURLSessionDataTask * dataTask =[defaultSession dataTaskWithRequest:urlRequest
completionHandler:^(NSData *data, NSURLResponse *response, NSError *error) {
NSLog(@"Response:%@ %@\n", response, error);
if(error == nil)
{
Nsstring * text = [[Nsstring alloc] initWithData: data encoding: NSUTF8StringEncoding];
NSLog(@"Data = %@",text);
[[NSUserDefaults standardUserDefaults]setobject:@"Y" forKey:@"login"];
[[NSUserDefaults standardUserDefaults] synchronize];
}
}];
[dataTask resume];
对于这段代码,我得到的反应如下:
在这里,我需要访问我的应用程序中的user_id.所以我可以得到特定的user_id.
谢谢.
解决方法:
由于原始解决方案已经发布,我将专注于更长和更长更麻烦的方式,我认为是在房间里处理大象的正确方法.从长远来看,这将对您有所帮助.
SharedUser.h
#import <Foundation/Foundation.h>
@interface SharedUser : NSObject
@property (strong, nonatomic) Nsstring* userId;
@property (strong, nonatomic) Nsstring* userName;
@property (strong, nonatomic) Nsstring* subscriptionStatus;
@property (strong, nonatomic) Nsstring* registerDate;
@property (strong, nonatomic) Nsstring* expiryDate;
+(SharedUser*) getInstance;
@end
SharedUser.m
#import "SharedUser.h"
@implementation SharedUser
static SharedUser * sharedInstance;
+(SharedUser*) getInstance
{
@synchronized(self)
{
if(sharedInstance == nil)
{
sharedInstance = [[SharedUser alloc] init];
sharedInstance.userName = @"";
sharedInstance.userId = @"";
sharedInstance.subscriptionStatus = @"";
sharedInstance.registerDate = @"";
sharedInstance.expiryDate = @"";
return sharedInstance;
}
else
{
return sharedInstance;
}
}
}
将您的回复转换为NSDictionary.
NSDictionary *json_dict = [NSJSONSerialization JSONObjectWithData:data options:0 error:&error];;//From Santosh Reddy's Answer
使用结果属性填充您的sharedInstance:
[SharedUser getInstance].userId = [json_dict objectForKey:@"user_id"];
[SharedUser getInstance].userName = [json_dict objectForKey:@"username"];
[SharedUser getInstance].subscriptionStatus = [json_dict objectForKey:@"subscription_status"];
[SharedUser getInstance].registryDate = [json_dict objectForKey:@"register_date"];//Better to use NSDate type instead of Nsstring
[SharedUser getInstance].expiryDate = [json_dict objectForKey:@"expiry_date"];
现在,您的用户属性将在应用程序的任何位置可用.您只需要将SharedUser.h导入到所需的UIView,UIViewController&键入以下内容以访问您的数据:
Nsstring *userId = [SharedUser getInstance].userId;
另请注意,我使用的是单例模式,因为我假设您只需要处理一个用户的属性,这些属性将在一段时间内用于多个视图控制器.如果您需要保存多个用户,请创建一个类似的用户模型类,并以类似的方式填充它们. (只是不要让他们单身).
另外我建议您阅读Ray Wenderlich的系列教程:
1. Object Oriented Design
2. Design Patterns
3. Intro to iOS design patterns
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