ios – 关闭Popover并点击一下即可打开新的

关于弹出窗口的苹果公司的“移动人机接口指南”说：

When possible,allow people to close one popover and open a new one
with one tap. This behavior is especially desirable when several
different bar buttons each open a popover,because it prevents people
from having to make extra taps.

我现在能想到的唯一解决方案是在解除弹出窗口时跟踪触摸的位置,并检查是否是另一个按钮的位置.
有没有更简单的方法来做到这一点？

PS：我在stackoverflow中搜索并在发布之前用Google搜索了一段时间.对不起,如果之前有人问这个问题.

UPDATE

我想我没有很好地解释自己.假设我有三个按钮.所有人都打开了一个弹出窗口.我的用户点击按钮#1并打开一个弹出窗口.当弹出窗口打开时,用户点击按钮#2. popover被解雇(因为用户点击了popover之外 – 非模态弹出窗口的默认行为)并且因为用户点击了按钮#2而打开了新的弹出窗口.所有这一切都无需点击两次：一次解除弹出窗口,两次打开新弹出窗口.

第二次更新

我建造了一个简单的假人来重现我正在尝试做的事情.当用户点击按钮并打开弹出窗口时,不会调用打开弹出窗口的方法.因此,用户必须单击两次才能打开第二个弹出窗口.有任何想法吗？

#import "RootViewController.h"
#import "AViewController.h"

@interface RootViewController() 

@property (nonatomic,retain) UIPopoverController *currentPopover;

@end

@implementation RootViewController

@synthesize currentPopover;

- (void)loadView
{
    CGRect applicationFrame = [[UIScreen mainScreen] applicationFrame];
    UIView *view = [[UIView alloc] initWithFrame:applicationFrame];

    CGRect buttonFrame = CGRectMake(50,100,200,40);

    for (int i = 0; i < 3; i++) 
    {

        UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
        [button setTitle:[Nsstring stringWithFormat:@"Button %i",i + 1] forState:UIControlStatenormal];
        [button addTarget:self action:@selector(openPopover:) forControlEvents:UIControlEventTouchDown];
        [button setFrame:buttonFrame];
        [view addSubview:button];

        buttonFrame.origin.y += 50;
    }


    self.view = view;
    [view release];
}

- (IBAction)openPopover:(id)sender
{
    AViewController *avc = [[AViewController alloc] init];
    UINavigationController *navigationController = [[UINavigationController alloc] initWithRootViewController:avc];
    [avc release];

    UIPopoverController *tempPopover = [[UIPopoverController alloc] initWithContentViewController:navigationController];
    [tempPopover setDelegate:self];
    [tempPopover setPopoverContentSize:CGSizeMake(320,500)];
    [tempPopover presentPopoverFromrect:[sender frame] inView:[self view] permittedArrowDirections:UIPopoverArrowDirectionLeft animated:YES];

    self.currentPopover = tempPopover;
    [tempPopover release];


    [navigationController release];
}

- (void)dealloc
{
    [currentPopover release];
    [super dealloc];
}

@end

解决方法

如果在工具栏中使用条形按钮项,则在点击另一个条形按钮项时,不会自动关闭打开的弹出框.在这些情况下,您应该关闭可见的弹出窗口并一步打开另一个弹出窗口.