我已经按照以下方式编写了一个方法:
if (something) { return 1; } the rest of the code
在我看来,该方法返回1,然后执行其余的代码.真的可以吗不返回停止代码的执行.它不是,我如何强制一种方法停止?
这是代码(根据要求):
for (int i=availableTime; i>0; i=i-1) { final int sec = i; SwingUtilities.invokelater(new Runnable() { public void run() { String lbl = "<html>"; lbl += "</html>"; timeLeftLabel.setText(lbl); } }); try {Thread.sleep(1000);} catch (InterruptedException e) {} parameterFromClientsListener = clientsListener.getValue(userName,parameterToGet); if (!parameterFromClientsListener.equals("null")) { output = parameterFromClientsListener; game.log.fine(userName + " set (by button) " + parameterToGet + " to be equal to " + output + " . [IMPORTANT]"); return output; } } game.log.fine("The partner selection phase is expired."); // This code is executed if the Submit button was not pressed and the time run out. if (parameterToGet.equals("partner")) { tellMyChoice(parameterToGet,this.partnerFromForm,"timer of" + field); output = this.partnerFromForm; } game.log.fine(parameterToGet + " was submitted by timer (not by OK button)."); } else { output = parameterFromClientsListener; } game.log.fine(userName + " set (by timer)" + parameterToGet + " to be equal to " + output + " . [IMPORTANT]"); return output; }
我运行这段代码两次.在每种情况下,我都会生成一个日志文件.在两个日志文件中,我看到“set(by button)”语句(在返回之前是直接的).但问题是在第二个日志文件中我看到“timer of”语句.如果达到“设定(按钮)”,则不能达到.怎么会这样?我需要提到的是,“set(by button)”和“timer”不会发生在我的代码中的任何地方(它们只发生一次).
添加3
从代码可以看出,我没有finally语句.
解决方法
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