java – 如何在单个命令中编译多个proto文件？

我在单个目录中有两个proto文件,我正在寻找一种方法,可以在单个命令中从这些文件生成类. Protobuf文档说我们需要使用–proto_path参数.

C:\shekhar\proto_trial>dir
 Volume in drive C is C

 Directory of C:\shekhar\proto_trial

07/25/2014  12:16 PM    <DIR>          .
07/25/2014  12:16 PM    <DIR>          ..
07/25/2014  12:16 PM    <DIR>          java_op
07/25/2014  12:16 PM               230 map.proto
07/23/2014  04:24 PM               161 message.proto
07/25/2014  12:17 PM             1,228 response.proto
               3 File(s)          1,619 bytes
               3 Dir(s)  50,259,398,656 bytes free

我使用了–proto_path参数,如下所示

C:\shekhar\proto_trial>protoc 
                       --proto_path=C:\shekhar\proto_trial 
                       --java_out=C:\shekhar\proto_trial\java_op 
                       *.proto

但我得到以下错误

message.proto: File does not reside within any path specified using --proto_path (or -I). 
You must specify a --proto_path which encompasses this file. 
Note that the proto_path must be an exact prefix of the .proto file names -- protoc is too dumb to figure out when two paths (e.g. absolute and relative) are equivalent (it's harder than you think).

请建议一些单独编译所有原型文件的方法.

解决方法

问题是您将–proto_path指定为绝对路径,但将proto文件指定为相对路径.您可以删除–proto_path参数(无论如何都默认为当前目录),或者您可以执行以下操作：

protoc --proto_path=C:\shekhar\proto_trial
       --java_out=C:\shekhar\proto_trial\java_op
       C:\shekhar\proto_trial\*.proto

原文地址：https://www.jb51.cc/java/125529.html