java – 密码包含@时,“期望/遵循URI中的主机名”异常

我正在尝试将本地系统文件复制到服务器

package classes;
import java.io.File;
import java.io.FileInputStream;
import java.io.InputStream;
import java.util.Properties;
import org.apache.commons.vfs.FileObject;
import org.apache.commons.vfs.FileSystemOptions;
import org.apache.commons.vfs.Selectors;
import org.apache.commons.vfs.impl.StandardFileSystemManager;
import org.apache.commons.vfs.provider.sftp.SftpFileSystemConfigBuilder;
public class SendMyFiles {
 public static void main(String[] args) {
  SendMyFiles sendMyFiles = new SendMyFiles();
  String filetoFTP = "zcol_30092013.xls";
  sendMyFiles.startFTP(filetoFTP);
 }
 public boolean startFTP(String filetoFTP){
  Properties prop = new Properties();
  InputStream in = getClass().getResourceAsstream("/config.properties");
  StandardFileSystemManager manager = new StandardFileSystemManager();
  try {
   prop.load(in);
   String serverAddress = prop.getProperty("serverAddress").trim();
   String userId = prop.getProperty("userId").trim();
   String password = prop.getProperty("password").trim();
   String remoteDirectory = prop.getProperty("remoteDirectory").trim();
   String localDirectory = prop.getProperty("localDirectory").trim();
   System.out.println("Cheking values "+serverAddress+" "+userId+" "+password+" "+remoteDirectory+" "+localDirectory);
   //check if the file exists
   String filepath = localDirectory;
   System.out.println("filepath "+filepath);
   File file = new File(filepath);
   System.out.println(file+" "+file.exists());
   if (!file.exists())
    throw new RuntimeException("Error. Local file not found");
   //Initializes the file manager
   manager.init();
   //Setup our SFTP configuration
   FileSystemOptions opts = new FileSystemOptions();
   SftpFileSystemConfigBuilder.getInstance().setStrictHostKeyChecking(
     opts,"no");
   SftpFileSystemConfigBuilder.getInstance().setUserDirIsRoot(opts,true);
   SftpFileSystemConfigBuilder.getInstance().setTimeout(opts,10000);
   //Create the SFTP URI using the host name,userid,password,remote path and file name
    String sftpUri= "sftp://" + userId + ":" + password + "@" + serverAddress + "/"
    + remoteDirectory+ filetoFTP;
   // Create local file object
    System.out.println("sftp uri "+sftpUri);
   System.out.println(file.getAbsolutePath());
   FileObject localFile = manager.resolveFile(file.getAbsolutePath());
   // Create remote file object
   FileObject remoteFile = manager.resolveFile(sftpUri,opts);
   // copy local file to sftp server
   remoteFile.copyFrom(localFile,Selectors.SELECT_SELF);
   System.out.println("File upload successful");
  }
  catch (Exception ex) {
   ex.printstacktrace();
   return false;
  }
  finally {
   manager.close();
  }
  return true;
 } 
}

在执行以下异常的代码时：

org.apache.commons.vfs.filesystemexception: Invalid absolute URI "sftp://vmsorbit:***@172.16.16.148/universe/files/zcol_30092013.xls".
    at org.apache.commons.vfs.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:62)
    at org.apache.commons.vfs.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:692)
    at org.apache.commons.vfs.impl.DefaultFileSystemManager.resolveFile(DefaultFileSystemManager.java:620)
    at classes.SendMyFiles.startFTP(SendMyFiles.java:67)
    at classes.SendMyFiles.main(SendMyFiles.java:23)
Caused by: org.apache.commons.vfs.filesystemexception: Expecting / to follow the hostname in URI "sftp://vmsorbit:***@172.16.16.148/universe/files/zcol_30092013.xls".
    at org.apache.commons.vfs.provider.HostFileNameParser.extractToPath(HostFileNameParser.java:155)
    at org.apache.commons.vfs.provider.URLFileNameParser.parseUri(URLFileNameParser.java:49)
    at org.apache.commons.vfs.provider.AbstractFileProvider.parseUri(AbstractFileProvider.java:188)
    at org.apache.commons.vfs.provider.AbstractOriginatingFileProvider.findFile(AbstractOriginatingFileProvider.java:58)
    ... 4 more

在线获得错误

FileObject localFile = manager.resolveFile(file.getAbsolutePath());

密码包含特殊字符@.

解决方法

如果您的密码包含@,则URL解析器将其视为userinfo – hostname分隔符.然后它会扫描一个主机名,在下一个@上停止,它会分隔实际的主机名.接下来,它检查主机名后面的第一个字符是/,它不是什么,因为它是@.逻辑对我来说没有多大意义,但解释了令人困惑的错误信息

Expecting / to follow the hostname in URI

但无论如何,即使逻辑更好,你的密码或用户名也不能有文字@.您必须将其URL编码为@.

如果您的用户名/密码是可变的,您应该使用UriParser.encode更好地对其进行编码：

public static String encode(String decodedStr)

请注意,文档中的注释是错误的.它说方法“从字符串中删除％nn编码.”,而它实际上添加了它们.

原文地址：https://www.jb51.cc/java/127846.html