java – 从xhtml文件创建jsf视图/组件树

我需要在应用程序启动时访问jsf页面组件树.我在网上找到了这个来源

UIViewRoot viewRoot = context.getApplication().getViewHandler().createView(context,"/path/to/some.xhtml");

但是生成的viewRoot没有任何子节点.
有谁知道最好的方法是什么？

谢谢.

解决方法

你忘了构建视图了.您可以使用 ViewDeclarationLanguage#buildView().这是 javadoc(强调我的)的摘录：

Take any actions specific to this VDL implementation to cause the argument UIViewRoot which must have been created via a call to 07002,to be populated with children.

因此,这应该做：

String viewId = "/path/to/some.xhtml";
FacesContext context = FacesContext.getCurrentInstance();
ViewHandler viewHandler = context.getApplication().getViewHandler();

UIViewRoot view = viewHandler.createView(context,viewId);
viewHandler.getViewDeclarationLanguage(context,viewId).buildView(context,view);
// view should Now have children.

你可以顺便使用ViewDeclarationLanguage#createView()直接创建视图而不是ViewHandler#createView()的速记.

String viewId = "/path/to/some.xhtml";
FacesContext context = FacesContext.getCurrentInstance();
ViewDeclarationLanguage vdl = context.getApplication().getViewHandler().getViewDeclarationLanguage(context,viewId);

UIViewRoot view = vdl.createView(context,viewId);
vdl.buildView(context,view);
// view should Now have children.

原文地址：https://www.jb51.cc/java/128690.html