javascript-如何处理看起来像这样的对象

我需要以表格形式显示错误.

如果在子级中定义了错误,则可以将错误附加到输入名称形式,这是常见情况(1).

但是可能会发生错误,该错误是在json对象的根节点中定义的(2).
在这种情况下,应将其附加到formElement上.

以下代码(3)适用于情况(1),但不适用于情况(2).

为了使其在两种情况下均能工作,我应该如何对其进行修改？
附注：我正在使用下划线和jQuery.

(1)

var xhrObj_1 = JSON.parse('{ "children":{"points":{"errors":["This value should not be blank."]},"message":[],"recipient_id":{"errors":["This value should not be blank."]}}}');

(2)

var xhrObj_2 = JSON.parse('{ "errors":["This form should not be …."], "children":{"points":{"errors":["This value should not be blank."]},"message":[],"recipient_id":{"errors":["This value should not be blank."]}}}');

(3)

var parser = function (object) {
    _.each(object, function (xhrObject, name) {
        console.log(xhrObject)

        if (xhrObject.errors) {
            var inputElement = element.find('[name="' + name + '"]');

            inputElement.closest('.control-group')
                .addClass('error');

            parserError(xhrObject.errors, inputElement);

        } else {
            parser(xhrObject); // it is ok for xhrObj_1
                               // it fails for xhrObj_2
        }
    });
};

// example with xhrObj_2 which does not work
parser({
    "errors": ["errro1"],
    "children": {
        "points": {
            "errors": ["This value should not be blank."]
        },
        "message": [],
        "recipient_id": {
            "errors": ["This value should not be blank."]
        }
    }
});

解决方法:

您应该在顶层开始递归：

var xhr = JSON.parse("…");

(function recurse(obj, name) {
    if (obj.errors) {
        var inputElement = element.find('[name="' + name + '"]');
        inputElement.closest('.control-group').addClass('error');
        parserError(obj.errors, inputElement);
    }
    if ("children" in obj)
        for (var prop in obj.children)
            recurse(obj.children[prop], prop);
})(xhr, "top");